我必须通过发送POST请求获得User
:
POST http://myurl.com/rest/user/getbyusername/{user} HTTP/1.0
token: uonIQz8WNE7UB5iR2V0ZYQ==
User-Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.0;)
Pragma: no-cache
Content-Length: 0
Host: myurl.com
我正在尝试使用这段代码:
private User getByUsername(String username) {
RestTemplate restTemplate = new RestTemplate();
HttpHeaders headers = new HttpHeaders();
List<String> list = new ArrayList<>();
list.add(Params.token);
headers.put("token", list);
return restTemplate.postForObject("http://myurl.com/rest/user/getbyusername/{username}", headers, User.class,
username);
}
控制器:
@ResponseBody
@RequestMapping(value = "getbyusername/{username}",
produces = "application/json",
method=RequestMethod.POST)
public String getByUsername(@PathVariable("username")
String username, HttpServletRequest request)
throws IOException {
if (!request.getHeader(headerName).isEmpty() && StringUtils.isNotBlank(token)
&& request.getHeader(headerName).equals(token)) {...}
}
可悲的是结果是Error 404
。我的代码缺少某些东西还是我完全错了?提前致谢
答案 0 :(得分:2)
您无法像目前那样设置标头,您需要将请求包装在HttpEntity
中,例如:
RestTemplate restTemplate = new RestTemplate();
HttpHeaders headers = new HttpHeaders();
headers.set("token", Params.token);
HttpEntity<String> entity = new HttpEntity<>(username, headers);
restTemplate.postForObject("http://myurl.com/rest/user/getbyusername/{username}",
entity,
User.class);
postForObject
Javadocs中建议采用这种方法。
或者,您可以实现ClientHttpRequestInterceptor
,它会将token
标头附加到每个请求。然后,您可以在RestTemplate
:
restTemplate.setInterceptors(new LinkedList<>(new MyTokenHeaderAddingInterceptor()));
这样可以避免记住为每个请求发送标题。