Question

... SOOOOO

为什么这不会将内容更改为我的数据库？

＆＃13;

<?php
if(isset($_POST['submit']))
{
 	if( isset($_POST['post_body']) )
	{
		$post_body = $_POST['post_body'];
		$id  	 = $_POST['id'];
		$sql     = "UPDATE forum_post SET post_body='$post_body' WHERE post_id='$id'";
		$res 	 = mysqli_query($mysql, $sql);	
	}
    if( isset($_POST['post_title']) )
	{
		$post_title = $_POST['post_title'];
		$id  	 = $_POST['id'];
		$sql     = "UPDATE forum_post SET post_title='$post_title' WHERE post_id='$id'";
		$res 	 = mysqli_query($mysql, $sql);	        
	}
}
?>

＆＃13;

        <form action="<?php $_PHP_SELF ?>" method="POST" class="form-horizontal">
            <fieldset>
                
            <legend>Edit</legend>    
            <div class="form-group">
                <input type="hidden" name="id" value="<?php echo $post_id; ?>">
                <label for="inputTitle" class="col-lg-2 control-label">Title</label>
                <div class="col-lg-5">
                    <input type="text" class="form-control" id="post_title" name="post_title" placeholder="<?php echo $post_title; ?>"  value="<?php echo $post_title; ?>">         
                </div>
            </div>
            <div class="form-group">
                <label for="inputTitle" class="col-lg-2 control-label">Created</label>
            <div class="col-lg-5">
                <p><?php echo $post_created;?></p>        
            </div>
            </div>
                <div class="form-group">
                <label for="textArea" class="col-lg-2 control-label">Textarea</label>
                <div class="col-lg-10">
                <textarea type="text" name="post_body" id="post_body" rows="8" class="col-md-12" value="<?php echo $post_body; ?>" class="form-control" rows="3">
                <?php echo $post_body; ?>
                </textarea>
                <span class="help-block">Here goes the content.</span>
                </div>
                <div class="col-md-2"><a href class="col-md-2 btn btn-danger btn-block" ng-show="showme" ng-click="showme=false">Back</a></div>             
                <input class="pull-right col-md-10 btn btn-primary btn-default" id="submit" type="submit" value="Submit" name="submit"/>
                </div>
            </fieldset>
        </form>

＆＃13;

我想要更新我的帖子内容＆amp;现在的头衔。为什么这不更新我的数据库？我什么也看不到错误。

我可以填写表格，按更新，没有错误。控制台也是空的。

问题是什么？

Answer 1

你必须逃避你的价值观。

$sql     = "UPDATE forum_post SET post_body='$post_body' WHERE post_id='$id'";

可能是：

$sql     = "UPDATE forum_post SET post_body='".$post_body."' WHERE post_id='".$id."'";

关于注射的警告！

Answer 2

尝试像这样回应错误mysql_error()

<?php
if(isset($_POST['submit']))
{
    if( isset($_POST['post_body']) )
    {
        $post_body = $_POST['post_body'];
        $id      = $_POST['id'];
        $sql     = "UPDATE forum_post SET post_body='$post_body' WHERE post_id='$id'";
        $res     = mysqli_query($mysql, $sql);  
        if($res)
{
 echo "updated";
} else
{
 echo mysqli_error();
}

    }
    if( isset($_POST['post_title']) )
    {
        $post_title = $_POST['post_title'];
        $id      = $_POST['id'];
        $sql     = "UPDATE forum_post SET post_title='$post_title' WHERE post_id='$id'";
        $res     = mysqli_query($mysql, $sql);  
if($res)
{
 echo "updated";
} else
{
 echo mysqli_error();
}        
    }
}
?>

PHP SELF表单发布到数据库

2 个答案: