我尝试用谷歌搜索一个简单注册模式用于引导程序的示例,但在PHP中找不到任何直接示例。如果有人能指出我正确的方向,我真的很感激。非常感谢。哦,我的意思是整个过程,而不仅仅是输入。就像AJAX代码一样。
答案 0 :(得分:0)
网上有很多教程。你可以搜索它们,但这里有一个嵌入bootstrap模式的小技巧。请看下面的
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>Twitter Bootstrap Modals Example</title>
<meta name="description" content="Creating Modal Window with Twitter Bootstrap">
<link href="/twitter-bootstrap/twitter-bootstrap-v2/docs/assets/css/bootstrap.css" rel="stylesheet">
</head>
<body>
<div class="container">
<h2>Example of creating Modals with Twitter Bootstrap</h2>
<div id="example" class="modal hide fade in" style="display: none; ">
<div class="modal-header">
<a class="close" data-dismiss="modal">×</a>
<h3>This is a Modal Heading</h3>
</div>
<div class="modal-body">
<h4>Your Form</h4>
<form action="./action.php" class="form_submit" method="post">
<input >
<input >
<input >
<input >
<input type="submit">
</form>
</div>
<div class="modal-footer">
<a href="#" class="btn btn-success">Call to action</a>
<a href="#" class="btn" data-dismiss="modal">Close</a>
</div>
</div>
<p><a data-toggle="modal" href="#example" class="btn btn-primary btn-large">Launch demo modal</a></p>
</div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
<script src="/twitter-bootstrap/twitter-bootstrap-v2/js/bootstrap-modal.js"></script>
</body>
<script>
$(function(){
$(".form_submit").on("submit", function(){
jQuery.ajax({
type: 'POST',
data: jQuery('.form_submit').serialize(),
url: jQuery('.form_submit').attr('action'),
dataType: 'json',
success: function (response) {
if (response.status == true) {
alert(response.message);
}
else {
alert(response.message);
}
},
});
})
})
</script>
</html>
在PHP文件中,您可以使用sql数据库查询来保存表单字段。在action.php文件中写下以下代码
//Data base connection code.
//Save your form fields. You will get array under $_POST variable.
if($_POST){
//save values in database
$response["status"] = true;
$response["message"] = "Data Savaed";
}else{
$response["status"] = false;
$response["message"] = "Data not Savaed";
}
echo json_encode($response);
exit();
答案 1 :(得分:0)
只需在模态正文中添加注册表单,有点像:
<div class="modal fade bs-example-modal-lg" tabindex="-1" role="dialog" aria-labelledby="myLargeModalLabel" aria-hidden="true" id="myModal">
<div class="modal-dialog modal-lg">
<div class="modal-content" style=" max-height: 600px;overflow-y: auto;overflow-x: hidden;">...your sign-up form here..</div>
</div>
</div>
创建一个按钮/链接来调用注册表单,如下所示:
<a href="#" class="alert-link" data-toggle="modal" data-target=".bs-example-modal-lg" id="add_user">Sign Up</a>
这是AJAX的示例:
$("#signup_form").on("submit", function (e) {
e.preventDefault();
$.ajax({
url: "save_person.php", //PHP FILE HERE
type: "post",
data: $(this).serialize(),
beforeSend: function () {
$("#success_person").show();
$("#success_person").html("Adding data to database...")
},
complete: function () {
$("#success_person").delay(3e3).fadeOut()
},
success: function (e) {
$("#success_person").show();
$("#success_person").html(e);
$("#success_person").delay(3e3).fadeOut();
$("#signup_form")[0].reset()
},
error: function (e, t, n) {
alert(e.status);
alert(n)
}
})
});
您认为PHP文件应如下所示:
require_once('../connection/connection.php');
if (isset($_POST["first_name"]) && !empty($_POST["first_name"])) {
$form_data = array();
//first column is your table field
//second is the name from your sign-up form
$form_data['title'] = mysql_real_escape_string($_POST['title']);
$form_data['first_name'] = mysql_real_escape_string($_POST['first_name']);
$form_data['middle_name'] = mysql_real_escape_string($_POST['middle_name']);
$form_data['last_name'] = mysql_real_escape_string($_POST['last_name']);
...
$tbl = "tblperson";
// retrieve the keys of the array (column titles)
$fields = array_keys($form_data);
// build the query
$sql = "INSERT INTO ".$tbl."
(`".implode('`,`', $fields)."`)
VALUES('".implode("','", $form_data)."')";
// run the query result resource
$result = mysql_query($sql);
if (!$result){
die('Invalid query: ' . mysql_error());
}
else{
echo "Successfully Added!";
}
}