出错:未知的系统调用20.汇编代码

时间:2015-02-12 02:53:43

标签: assembly mips risc

这是通过QTSpim运行的MIPS程序集中的程序,它以二次函数获取给定数字并显示抛物线。这是我的第一个低级程序之一,我不是任何形式的优秀程序员 因此,当我运行该程序时,它会显示未知的系统调用:20。这是我为该范围的上限输入的数字。我用来测试的数字是1,-1,-6表示系数,-10,10表示x轴,-10,20表示y。它应该显示一个抛物线,但它只显示X和Y轴。这是向前迈出的一步,因为昨天它不会显示任何东西。帮助!

.text
.globl main
main:
    la $a0,prompt1           # display "Enter the coeficiants of the quadratic: "
    li $v0,4
    syscall

    li $v0,5                 # enter A -> v0
    syscall
    move $t0,$v0             # t0 <--- v0

    li $v0,5                 # enter B -> v0
    syscall
    move $t1,$v0             # t1 <--- v0

    li $v0, 5                # enter C -> v0
    syscall
    move $t2,$v0             # t2 <--- v0

    la $a0,prompt2           # display "Enter the lower (first) and upper (second) bounds of the domain: "
    li $v0, 4
    syscall

    li $v0, 5                # enter lower bound -> v0
    syscall
    move $t3, $v0            # t3 <--- v0

    li $v0, 5                # enter upper bound -> v0
    syscall
    move $t4, $v0            # t4 <--- v0

    la $a0, prompt3          # display "Enter the lower (first) and upper (second) bounds of the range: "
    li $v0, 4
    syscall

    li $v0, 5                # enter lower bound -> v0
    syscall
    move $t6, $v0            # t6 <--- v0

    li $v0, 5                # enter upper bound -> v0
    syscall
    move $t7, $v0            # t7 <--- v0

    move $t8, $t7            # t8 <--- t7
    syscall

step10: move $t9, $t3            # t9 <--- t3
    syscall

step11: mul $t5,$t3,$t0          # t0 * t3 -> t5
    add $t5,$t1,$t5          # t5 + t1 -> t5
    mul $t5,$t5,$t3          # t5 * t3 -> t5
    add $t5,$t5,$t2          # t5 + t2 -> t5

    beq $t8, $t5, point      # if y = f(x) goto point marker

    beqz $t9, yaxis          # if x = 0 goto yaxis

    beqz $t8, xaxis          # if y = 0 goto xaxis

    la $a0,space             # display " "
    li $v0,4
    syscall

step16: beq $t9, $t4, newl       # if x = x-max goto newl

    add $t9, $t9, 1          # $t9 += 1

    j step11

step18: beq $t8, $t6, EOP        # if y = y-min end program

    sub $t8, $t8, 1          # $t8 -= 1

    j step10

EOP:    li $v0,10                # EOP
    syscall

newl:   la $a0,endl              # display "\n"
    li $v0,4
    syscall        
    j step18

point:  la $a0,star              # display "*"
    li $v0,4
    syscall
    j step16

yaxis:  la $a0,bar               # display "|"
    li $v0,4
    syscall
    j step16

xaxis:  la $a0,hyph              # display "-"
    li $v0,4
    syscall
    j step16


    .data
prompt1: .asciiz "Enter the coeficiants of the quadratic: "
prompt2: .asciiz "Enter the lower (first) and upper (second) bounds of the domain: "
prompt3: .asciiz "Enter the lower (first) and upper (second) bounds of the range: "
bar:     .asciiz "|"
star:    .asciiz "*"
hyph:    .asciiz "-"
space:   .asciiz " "
endl:    .asciiz "\n"

1 个答案:

答案 0 :(得分:0)

所以,当你正在阅读输入时,你会去:

[...]
    li $v0, 5                # enter upper bound -> v0
    syscall
    move $t7, $v0            # t7 <--- v0

    move $t8, $t7            # t8 <--- t7
    syscall                  #$v0 is still whatever user input for upper bound

step10: move $t9, $t3        # t9 <--- t3
    syscall                  #$v0 is whatever the last (unspecified) syscall returned

我不知道您想要致电的syscall,所以我无法帮助您。我建议在编写汇编之前用更高级的语言编写代码。