Question

正如标题所述，我希望创建一个char数组，用户输入应该存储为char。我这样做是为了创建错误的代码，它可能成为缓冲区溢出的牺牲品。我有这个工作后，我将截断输入，而不是导致缓冲区溢出。但是当我被指示这样做时，我无法弄清楚如何将我的字符串存储为Java中的char。这是我到目前为止的代码：

import java.util.Scanner;





public class buggyCode {

public buggyCode() {
    // TODO Auto-generated constructor stub
}

public static void main(String[] args) {
    // TODO Auto-generated method stub
    Scanner kb = new Scanner(System.in);
    String input1, input2, input3, input4, input5, input6, input7, input8, input9, input10;
    char[] thisArray = new char [150];

    thisArray[0]=toChar(input1);
    thisArray[1]=input2;
    thisArray[3]=input3;


    System.out.println("Enter some characters. We are going to do this for a while");
    input1 = kb.nextLine();
    System.out.println("Enter some characters. We are going to do this for a while");
    input2 = kb.nextLine();
    System.out.println("Enter some characters. We are going to do this for a while");
    input3 = kb.nextLine();
    System.out.println("Enter some characters. We are going to do this for a while");
    input4 = kb.nextLine();
    System.out.println("Enter some characters. We are going to do this for a while");
    input5 = kb.nextLine();
    System.out.println("Enter some characters. We are going to do this for a while");
    input6 = kb.nextLine();
    System.out.println("Enter some characters. We are going to do this for a while");
    input7 = kb.nextLine();
    System.out.println("Enter some characters. We are going to do this for a while");
    input8 = kb.nextLine();
    System.out.println("Enter some characters. We are going to do this for a while");
    input9 = kb.nextLine();
    System.out.println("Enter some characters. We are going to do this for a while");
    input10 = kb.nextLine();

}

}

Answer 1

首先，这行代码会在启动程序时自动失败，删除它：

thisArray[0]=toChar(input1);
thisArray[1]=input2;
thisArray[3]=input3;

要使用干净的代码，您可以使用字符串丢弃，然后使用for loop

循环它们

for(int i = 0; i < 10; i++)
{
    System.out.println("Enter some characters. We are going to do this for a while");
    thisArray[i] = kb.nextLine().toCharArray()[0]; //store the first index of string to the thisArray array
}

上面你可以看到nextLine（）然后被转换为char数组并获得第一个索引然后存储在ur char数组

Answer 2

每次你写inputN两次以上，N被数字替换，你就知道你需要一个数组。大多数情况下，当您发现自己通过最少的更改复制粘贴代码时，您就知道需要循环。

我要在每10个索引处填充数组，从150开始下降。

以下是如何正确地做到这一点：

char[] input = new char[150];
for (int i = 0 ; i != 10 ; i++) {
    System.out.println("Enter some characters. We are going to do this for a while.");
    char[] buf = kb.nextLine().toCharArray();
    // Copy the data into input
    System.arraycopy(buf, 0, input, 140-(i*10), Math.min(buf.length, 10));
}

如何将字符串转换为char来填充Java中的数组？

2 个答案: