如何连接字符串而不必多次输入？

Question

有没有办法写它所以我不必输入+ str（random.choice（string.ascii_uppercase））3次？

strip 1 ''.join([c for c in s if c not in ('!',' ',',',)])
strip2 = strip1 + str(random.choice(string.ascii_uppercase))+ str(random.choice(string.ascii_uppercase))+ str(random.choice(string.ascii_uppercase))
return (strip2)

Answer 1

使用for loop

strip2 = strip1 

for i in range(3):

    strip2 += str(random.choice(string.ascii_uppercase))

Answer 2

list comprehension + range：

strip2 = strip1 + ''join([str(random.choice(string.ascii_uppercase)) for x in range(3)])