Rails没有使用模型指定的表

时间:2015-02-11 19:56:33

标签: ruby-on-rails ruby rspec factory-bot

我有一个继承另一个模型的模型,这个特定的模型不使用我指定的表,而是默认返回到尝试查找该表的父类。

父类位于gem中,子类位于引擎中,其名称空间是隔离的。

父级(在宝石中):

require_relative 'concerns/user_concerns'
require 'bcrypt'

module CoreModels
  module Models
    class User < ActiveRecord::Base
      self.abstract_class = true

      extend FriendlyId
      friendly_id :first_name, use: [:slugged, :finders, :history]

      before_save :encrypt_password

      has_many :group_memberships, :dependent => :delete_all
      has_many :groups, :through => :group_memberships, :dependent => :delete_all
      has_many :roles, :through => :group_memberships, :dependent => :delete_all

      has_many :api_keys

      validates :first_name, presence: true
      validates :user_name, uniqueness: true, presence: true, length: {minimum: 5}
      validates :email, presence: true, confirmation: true, uniqueness: true
      validates_format_of :email, :with => /\A([^@\s]+)@((?:[-a-z0-9]+\.)+[a-z]{2,})\z/i
      validates :password, presence: true, confirmation: true, length: { minimum: 10 }, if: :new_record?

      include CoreModels::Models::Concerns::UserConcerns

      before_create{ generate_token(:auth_token) }

      def self.authenticate_user(user_name, password)
        user = Xaaron::User.find_by_user_name(user_name)
        if(user && (user.password == BCrypt::Engine.hash_secret(password, user.salt)))
          user
        else
          nil
        end
      end

      def encrypt_password
        if password.present?
          self.salt = BCrypt::Engine.generate_salt
          self.password = BCrypt::Engine.hash_secret(password, salt)
        end
      end

      def send_password_reset
        generate_token(:password_reset_token)
        self.password_reset_timestamp = Time.zone.now
        save!
        UserMailer.password_reset(self).deliver
      end

      protected
      def generate_token(column)
        begin
          self[column] = SecureRandom.urlsafe_base64
        end while User.exists?(column => self[column])
      end
    end
  end
end

儿童(在引擎中):

require 'core_models/models/user'

module Xaaron
  class User < CoreModels::Models::User
    self.table_name = 'xaaron_users'
  end
end

当我运行我的测试时,其中135次失败一遍又一遍地给我同样的错误:

Failure/Error: setup_group_role_permissions_relations_for_administrator
     ActiveRecord::StatementInvalid:
       PG::UndefinedTable: ERROR:  relation "users" does not exist
       LINE 5:                WHERE a.attrelid = '"users"'::regclass
                                                 ^
       :               SELECT a.attname, format_type(a.atttypid, a.atttypmod),
                            pg_get_expr(d.adbin, d.adrelid), a.attnotnull, a.atttypid, a.atttypmod
                       FROM pg_attribute a LEFT JOIN pg_attrdef d
                         ON a.attrelid = d.adrelid AND a.attnum = d.adnum
                      WHERE a.attrelid = '"users"'::regclass
                        AND a.attnum > 0 AND NOT a.attisdropped
                      ORDER BY a.attnum

这种特殊方法是:

def setup_group_role_permissions_relations_for_administrator
  @user = FactoryGirl.create(:user)
  @role = FactoryGirl.create(:admin_role)
  @group = FactoryGirl.create(:administrator_group)
  @permission = FactoryGirl.create(:can_read)

  @role.add_permission = @permission.permission_name
  @group.add_role = @role.role_name

  @user.add_group_membership(@group, @role)
end

所以当我说使用表x时你可以看到它没有听我说话。相反,它试图使用一个不存在的表./我的所有引擎表的名称都用xaaron_

分隔

更新

经过一些调查后,核心问题是FactoryGirl,如果我们看一下发生的第一件事:setup_group_role_permissions_relations_for_administrator我正在做@user = FactoryGirl.create(:user),当我用pry来弄清楚那里发生了什么 - 这就是问题,所以让我们来看看这家工厂:

FactoryGirl.define do
  sequence :user_email do |n|
    "user#{n}@example.com"
  end

  # Allows for multiple user names
  sequence :user_name do |n|
    "user#{n}"
  end

  sequence :permission_name do |n|
    "can_read#{n}"
  end

  sequence :role_name do |n|
    "Member#{n}"
  end


  factory :user, :class => Xaaron::User do
    first_name 'Adam'
    last_name 'Something'
    user_name {generate :user_name}
    email {generate :user_email}
    password 'somePasswordThat_Is$ecure10!'
  end

  factory :admin, :class => Xaaron::User do
    first_name "Sample Admin"
    email "a@gmail.com"
    user_name "Admin_User_Name"
    password "admin_Password10985"
  end
end

工厂女孩创建用户的方式有问题,因为我可以启动rails控制台并执行Xaaron::User.all,它知道要查看xaaron_users而不是users

所以self.table_name=""有效,但由于某种原因,它不与工厂女孩合作。

更新2

我已在Their Github Repo

提交了可能的错误报告

1 个答案:

答案 0 :(得分:1)

通常,Active Record旨在使用单表继承(用于所有子类的记录的相同表)而不是多表继承(子类的不同表。)

也就是说,不是使用self.table_name =在子类中设置表名,而是可以尝试覆盖table_name方法,例如。

def table_name
  'xaaron_users'
end

并查看是否适用于您的方案。这是mentioned as an alternative in the docs