我希望从Report,Player和Fixture表中选择所有字段,其中Report表中的FixtureID与@FixtureID(从组合框中选择)匹配。但是,我无法使别名正常工作 - 我尝试使用与Report和Fixture相同的方式对Player表进行别名,但这也会引发错误。
SELECT
r.*,
Player.*,
f.*,
isNull(Player.PlayerFirstName + ' ' + Player.PlayerLastName, ' ') AS 'PlayerName'
FROM
Report AS r, Fixture AS f
INNER JOIN Player ON Player.PlayerID = r.PlayerID
INNER JOIN f ON f.FixtureID = r.FixtureID
WHERE
r.FixtureID = @FixtureID
ORDER BY
ReportDate
错误说明:"多部分标识符" r.PlayerID"不能被约束"。
任何建议都将不胜感激。
答案 0 :(得分:3)
试试这个......
SELECT r.*
,Player.*
,f.*
,isNull(Player.PlayerFirstName + ' ' + Player.PlayerLastName, ' ') AS 'PlayerName'
FROM Report AS r
INNER JOIN Player ON Player.PlayerID = r.PlayerID
INNER JOIN Fixture AS f ON f.FixtureID = r.FixtureID
WHERE r.FixtureID = @FixtureID
ORDER BY ReportDate