我有一些像这样的代码:
form IPython import embed
for item in my_item_list:
embed()
如果我随后用
运行此程序python my_example_program.py
在循环的第一次迭代中,我被放入一个ipython shell中,可以按照我的意愿检查item
和环境。
在退出ipython时,循环恢复,然后我可以按照您的预期检查下一个item
和环境。
有没有办法让我从ipython中退出这段代码(这样我就会返回shell提示符)。在任何方面都没有打开另一个shell并杀死进程?
答案 0 :(得分:13)
IPython中有一个%kill_embedded
命令
它不会直接返回shell提示符,但会跳过其他嵌入实例。
from IPython import embed
for item in range(5):
print 'embedding', item
embed()
这是输出:
$ python my_example_program.py
embedding 0
Python 2.7.9 (default, Dec 13 2014, 22:30:33)
Type "copyright", "credits" or "license" for more information.
IPython 1.1.0 -- An enhanced Interactive Python.
? -> Introduction and overview of IPython's features.
%quickref -> Quick reference.
help -> Python's own help system.
object? -> Details about 'object', use 'object??' for extra details.
In [1]: print item
0
In [2]: ^D
embedding 1
Python 2.7.9 (default, Dec 13 2014, 22:30:33)
Type "copyright", "credits" or "license" for more information.
IPython 1.1.0 -- An enhanced Interactive Python.
? -> Introduction and overview of IPython's features.
%quickref -> Quick reference.
help -> Python's own help system.
object? -> Details about 'object', use 'object??' for extra details.
In [2]: %kill_embedded
Are you sure you want to kill this embedded instance (y/n)? [y/N] y
This embedded IPython will not reactivate anymore once you exit.
In [3]: print item
1
In [4]:
embedding 2
embedding 3
embedding 4
$
UPD(06.03.2016):似乎%kill_embedded
功能在IPython 4.0中有所破坏;您可以使用%exit_raise
来引发异常并返回shell。