Question

我有一张包含员工ID，账号，账户类型，银行ID和其他一些列的表BonusPay。

我需要编写在sql中返回非唯一Employee ID的查询

重复的员工ID +帐号+银行ID +帐户类型。组合必须是唯一的。

我写了查询来查找重复的员工ID

(SELECT [Employee ID],COUNT([Employee ID]) 
FROM [BASEP1].[INTERIM - Bonus Pay Election Enrollment] 
GROUP BY [Employee ID] 
HAVING COUNT([Employee ID])>1)

请帮助我进一步了解

表 **员工ID帐号银行ID号帐号类型
    DC21002 1042044011 121000358 SA
    DC21004 8840215401 271070801 DDA
    DC21005 9942011555 21000089 DDA
    DC21106 0033384728 NULL DDA
    DC21117 NULL 121000358 SA
    DC21053 0448921114 11000138 NULL
    DC21003 4505120541 121000248 DDA
    DC21007 5981285871 121000358 SA
    DC21095 5400147754 121000358 SA
    DC21095 0035793301 121000358 DDA
    DC21044 0493540121 121000248 SA
    DC21039 NULL NULL NULL

现在使用重复ID，与其他列合并。结果看起来像

select [Employee ID]+[Account Number]+[Bank ID Number]+[Account Type]
from [BASEP1].[INTERIM - Bonus Pay Election Enrollment]

DC210021042044011121000358SA
DC210048840215401271070801DDA
DC21005994201155521000089DDA
DC21117NULL121000358SA
现在检查结果组合是否唯一

Answer 1

将您的查询标识重复项放入公用表表达式，然后将重复的值加入原始表中以获得结果。

;with CTE as
(SELECT [Employee ID],COUNT([Employee ID]) 
FROM [BASEP1].[INTERIM - Bonus Pay Election Enrollment] 
GROUP BY [Employee ID] 
HAVING COUNT([Employee ID])>1)
select distinct employee ID
from [BASEP1].[INTERIM - Bonus Pay Election Enrollment] b
join cte a on a.[employee id] on b.[employee id]

Answer 2

如果我理解正确（如果我错了，请纠正我），那么你想要找到组合Employee ID+Account Number+Bank ID+Account Types的副本，然后只需按照它进行分组。这将对Employee ID+Account Number+Bank ID+Account Types

的uniq组合进行分组

    ;WITH CTE
      (
       SELECT [Employee ID],COUNT([Employee ID]) as duplicatecount
       FROM [BASEP1].[INTERIM - Bonus Pay Election Enrollment] 
       GROUP BY [Employee ID]
       HAVING COUNT([Employee ID])>1
      )
    Select c.EmployeeID,
           t.AccountNumber,
           t.BankID,
           t.AccountType
    FROM
        CTE c Join [BASEP1].[INTERIM - Bonus Pay Election Enrollment] t
         ON c.EmployeeID = t.EmployeeID

Answer 3

如果你想找到重复的行，你可以试试这个：

SELECT
    [Employee ID],
    [Account Number],
    [Bank ID],
    [Account Types],
    COUNT(*)
FROM
    [BASEP1].[INTERIM - Bonus Pay Election Enrollment] 
GROUP BY
    [Employee ID],
    [Account Number],
    [Bank ID],
    [Account Types]
HAVING
    COUNT(*) > 1

Answer 4

为什么这个陈述不起作用？：

SELECT [Employee ID]
    FROM [BASEP1].[INTERIM - Bonus Pay Election Enrollment] 
    GROUP BY [Employee ID] 
    HAVING COUNT([Employee ID])>1;

Answer 5

这个怎么样？

;WITH CTE
AS (
    SELECT *
        ,ROW_NUMBER() OVER (
            PARTITION BY [Employee ID]
            ,[Account Number]
            ,[Bank ID]
            ,[Account Types]
            order by [Employee ID]    
            ) ROWNUM
    FROM [BASEP1].[INTERIM - Bonus Pay Election Enrollment]
    )
SELECT *
    ,[Employee ID] + [Account Number] + [Bank ID] + [Account Types] + ROWNUM AS [New Employee ID]
FROM CTE

具有重复id的组合在sql中必须是唯一的

5 个答案: