我正在开发一个具有AJAX调用的简单Struts2应用程序。我正在尝试使用AJAX调用检查表单的每个字段，同时填充它。我想从servlet获得响应。为了调用servlet，我在struts.xml文件中使用了'exclude url'，并在web.xml文件中包含了ajax调用模式。但是我的应用程序无法找到servlet。以下是代码段：
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<script src="util.js" type="text/javascript"></script>
<script src="validate.js" type="text/javascript"></script>
<title>Employee Registration Form</title>
</head>
<body>
<h1 align="center">Employee Registration Form</h1>
<h2 align="left">Please provide your details in the appropriate fields. Fields marked with * are mandatory. </h2><br><br>
<s:form action="register">
<s:textfield id="username" name="username" label="Username*" />
<s:textfield name="fullname" label="Full Name*" />
<s:textfield name="emailid" label="Email*" />
window.onload = initPage;
alert("validate.js page");
function initPage() {
document.getElementById("username").onblur = checkUsername;
//document.getElementById("register").disabled = true;
alert("in initPage();");
}
function checkUsername() {
request=createRequest();
if(request==null)
alert("Unable to create request!");
else{
var theName = document.getElementById("username").value;
var username = escape(theName);
var url = "http://localhost:8080/PeopleManagement/checkName.do?username=" + username;
//var url = "checkName.do?username=" + username;
request.onreadystatechange = showUsernameStatus;
request.open("GET",url,true);
request.send(null);
alert("url:" + url);
}
alert("in checkUsername();");
}
function showUsernameStatus(){
if(request.readyState == 4){
if(request.status == 200){
alert("Status:" + request.statusText);
alert("Response:" + request.responseText);
if(request.statusText == "okay"){
alert("allowed");
}
else
alert("denied");
}
}
}
<package name="admin" extends="struts-default">
<action name="Welcome">
<result>/welcome.jsp</result>
</action>
<action name="Admin" class="com.admin.AdminUser" method="execute">
<result name="input">/adminLogin.jsp</result>
<result name="SUCCESS">/adminMenu.jsp</result>
</action>
</package>
<package name="registration" extends="struts-default">
<action name="register" class="com.emp.Employee" method="execute">
<result name="input">empForm.jsp</result>
<result name="error">/registrationError.jsp</result>
<result name="SUCCESS">/registrationSuccess.jsp</result>
</action>
<action name="viewemp" class="com.emp.ViewEMP" method="execute">
<result name="error">/viewError.jsp</result>
<result name="SUCCESS">/list.jsp</result>
</action>
</package>
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
<display-name>PeopleManagement</display-name>
<welcome-file-list>
<welcome-file>welcome.jsp</welcome-file>
</welcome-file-list>
<filter>
<filter-name>struts2</filter-name>
<filter-class>
org.apache.struts2.dispatcher.FilterDispatcher
</filter-class>
</filter>
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<servlet>
<servlet-name>UserValidator</servlet-name>
<servlet-class>com.validation.ValidateUser</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>UserValidator</servlet-name>
<url-pattern>/checkName.do*</url-pattern>
</servlet-mapping>
</web-app>
请帮帮我。
答案 0 :(得分：2)
您需要在web.xml中正确映射您的Servlet
<servlet-mapping>
<servlet-name>UserValidator</servlet-name>
<url-pattern>/PeopleManagement/checkName.do</url-pattern>
</servlet-mapping>
.........
[编辑] 您还必须编辑/ * to / struts拦截器servlet。这里解释了不同之处 - Difference between / and /* in servlet mapping url pattern