解析JSON时无法识别的选择器

Question

所以我下面的照片是我拍摄的JSON脚本的截图，我试图从URL中读取。在下面的代码部分中，我设法得到了＆＃39;名称＆＃39;属性并将其分配给＆＃39; name＆＃39; NSString对象，但是当我尝试为＆＃39;地址＆＃39;做同样的事情时我收到以下错误：

[__NSCFDictionary objectAtIndexedSubscript:]: unrecognized selector sent to instance 0x174260980
*** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[__NSCFDictionary objectAtIndexedSubscript:]: unrecognized selector sent to instance 0x174260980'

我在内部＆＃39;场地＆＃39;之间的区别是什么？比在里面＆＃39;位置＆＃39;？我尝试了很多不同的方法，有些包括数组，但似乎没有任何工作。

NSURL *url = [NSURL URLWithString:urlString];

NSData *jsonData = [NSData dataWithContentsOfURL:url];
NSError *error = nil;
NSDictionary *dataDictionary = [NSJSONSerialization JSONObjectWithData:jsonData options:0 error:&error];

NSDictionary *responseDictionary = [dataDictionary objectForKey:@"response"];
NSDictionary *venueDictionary = [responseDictionary objectForKey:@"venues"];

for (NSDictionary *dict in venueDictionary) {
    NSLog(@"%@", dict);
    NSString *name = [dict objectForKey:@"name"];
    NSDictionary *locationDictionary = [dict objectForKey:@"location"];
    for (NSDictionary *locationDict in locationDictionary) {
        NSString *address = [locationDict objectForKey:@"address"];
        NSLog(@"%@", address);
    }
}

Answer 1

你期望“location”键指向一个数组，但事实并非如此。它指向一个对象，摆脱for (NSDictionary *locationDict in locationDictionary) {而只是从locationDictionary中取出地址。