删除元音，除非它是单词的开头

Question

我正在尝试删除字符串中元音的出现，除非它们是单词的开头。例如，像"The boy is about to win"这样的输入应该输出Th by is abt t wn。这是我到目前为止所拥有的。任何帮助将不胜感激！

def short(s):
vowels = ('a', 'e', 'i', 'o', 'u')
noVowel= s
toLower = s.lower()
for i in toLower.split():
    if i[0] not in vowels:
        noVowel = noVowel.replace(i, '')        
return noVowel

Answer 1

一种方法是使用正则表达式替换不在单词边界之前的元音。此外，如果您的代码应该使用各种类型的标点处理任意文本，您可能需要考虑一些更有趣的测试用例。

import re
s = "The boy is about to win (or draw). Give him a trophy to boost his self-esteem."
rgx = re.compile(r'\B[aeiou]', re.IGNORECASE)
print rgx.sub('', s)  # Th by is abt t wn (or drw). Gv hm a trphy t bst hs slf-estm.

Answer 2

尝试：

>>> s = "The boy is about to win"
>>> ''.join(c for i, c in enumerate(s) if not (c in 'aeiou' and i>1 and s[i-1].isalpha()))
'Th by is abt t wn'

工作原理：

以上关键部分如果是发电机：

c for i, c in enumerate(s) if not (c in 'aeiou' and i>1 and s[i-1].isalpha())

生成器的关键部分是条件：

if not (c in 'aeiou' and i>1 and s[i-1].isalpha())

这意味着s中的所有字母都包括在内，除非它们不是（a）在s开头的元音，因此在单词的开头，或者（b）之前的元音用非字母表示它们只是一个单词的开头。

重写为for循环

def short(s):
    new = ''
    prior = ''
    for c in s:
        if not (c in 'aeiou' and prior.isalpha()):
            new += c
        prior = c
    return new

Answer 3

您可以在字符串的其余部分使用正则表达式（忽略第一个字符）：

import re
s = 'The boy is about to win'
s = s[0] + re.sub(r'[aeiou]', '', s[1:])
print s # Th by s bt t wn

Answer 4

使用正则表达式：

import re

re.sub("(?<!\b)[aeiouAEIOU]", '', s)

Answer 5

通过re.sub。

>>> import re
>>> s = "The boy is about to win"
>>> re.sub(r'(?i)(?<=\S)[aeiou]', r'', s)
'Th by is abt t wn'

\S匹配任何非空格字符。

Answer 6

>>> re.sub('(?<=\w)[aeiou]','',"The boy is about to win")
'Th by is abt t wn'