Question

如果我有两个列表（可能有不同的len）：

x = [1,2,3,4]
f = [1,11,22,33,44,3,4]

result = [11,22,33,44]

我正在做：

for element in f:
    if element in x:
        f.remove(element)

我得到了

result = [11,22,33,44,4]

Answer 1

如果你想要两个列表中的唯一元素，这应该有效：

x = [1,2,3,4]
f = [1,11,22,33,44,3,4]

res = list(set(x+f))
print(res)
# res = [1, 2, 3, 4, 33, 11, 44, 22]

Answer 2

基于new (closed) question中对此问题的澄清：

如果您希望第二个列表中的所有项目都没有出现在第一个列表中，您可以写下：

x = [1,2,3,4]
f = [1,11,22,33,44,3,4]

result = set(f) - set(x) # correct elements, but not yet in sorted order
print(sorted(result)) # sort and print

# Output: [11, 22, 33, 44]

Answer 3

在场景中使用这段Python's documentation：

>>> # Demonstrate set operations on unique letters from two words
...
>>> a = set('abracadabra')
>>> b = set('alacazam')
>>> a                                  # unique letters in a
{'a', 'r', 'b', 'c', 'd'}
>>> a - b                              # letters in a but not in b
{'r', 'd', 'b'}
>>> a | b                              # letters in a or b or both
{'a', 'c', 'r', 'd', 'b', 'm', 'z', 'l'}
>>> a & b                              # letters in both a and b
{'a', 'c'}
>>> a ^ b                              # letters in a or b but not both
{'r', 'd', 'b', 'm', 'z', 'l'}

我想出了这段代码来从两个列表中获取唯一元素：

(set(x) | set(f)) - (set(x) & set(f))

或稍作修改以返回list：

list((set(x) | set(f)) - (set(x) & set(f))) #if you need a list

这里：

|运算符返回x，f或两者
&运算符返回 x和f
-运算符从&中减去|的结果，并向我们提供仅在列表之一中唯一显示的元素

Answer 4

如果您只想从两个列表中获取唯一元素，那么您可以通过..

获取它

a=[1,2,3,4,5]
b= [2,4,1]
list(set(a) - set(b))
OP:- [3, 5]

Answer 5

x = [1, 2, 3, 4]

f = [1, 11, 22, 33, 44, 3, 4]

list(set(x) ^ set(f))

[33, 2, 22, 11, 44]

Answer 6

输入：

x = [1,2,3,4]

f = [1,11,22,33,44,3,4]

代码：

l = list(set(x).symmetric_difference(set(f)))
print(l)

输出：

[2, 22, 33, 11, 44]

Answer 7

您的方法不会获得唯一元素“2”。怎么样：

list(set(x).intersection(f))

Answer 8

v_child_value = [{'a':1}, {'b':2}, {'v':22}, {'bb':23}]
shop_by_cat_sub_cats = [{'a':1}, {'b':2}, {'bbb':222}, {'bb':23}]


unique_sub_cats = []
for ind in shop_by_cat_sub_cats:
    if ind not in v_child_value:
        unique_sub_cats.append(ind)

unique_sub_cats = [{＆＃39; bbb＆＃39;：222}]

Answer 9

Python代码从两个列表创建唯一列表：

a=[1,1,2,3,5,1,8,13,6,21,34,55,89,1,2,3]
b=[1,2,3,4,5,6,7,8,9,10,11,12,2,3,4]
m=list(dict.fromkeys([a[i] for i in range(0,len(a)) if a [i] in a and a[i] in b and a[i]]))

print(m)

Answer 10

L=[] 
For i in x:
    If i not in f:
        L. Append(I)
For i in f:
    If I not in x:
        L. Append(I)
Return L

从两个列表python中只获取唯一元素

10 个答案: