Question

使用multidb路由器，如何将所有django_ *表（模型）移动到另一个db而不是默认值（同时移动django_migrations表）？

通过“移动”，我接受简单地将它们放在另一个数据库中

编辑：好的，似乎django_migration无法移动并且存在于每个数据库......

但是使用该代码，我收到一个奇怪的错误：

网/ settings.py：

DATABASES = {
    'intern_db': {
        'ENGINE': 'mysql.connector.django',
        'NAME': 'django_cartons',
        'USER': 'root',
        'PASSWORD' : '',
    },
    'default': {
        'ENGINE': 'mysql.connector.django',
        'NAME': 'carton2',
        'USER': 'root',
        'PASSWORD' : '',
    }
}

DATABASE_ROUTERS = ['web.AuthRouter.AuthRouter']

网/ AuthRouter.py

class AuthRouter(object):
    """
    A router to control all database operations on models in the
    auth application.
    """
    def db_for_read(self, model, **hints):
        """
        Attempts to read auth models go to auth.
        """
        if model._meta.app_label == 'auth':
            return 'intern_db'
        return None

    def db_for_write(self, model, **hints):
        """
        Attempts to write auth models go to auth.
        """
        if model._meta.app_label == 'auth':
            return 'intern_db'
        return None

    def allow_relation(self, obj1, obj2, **hints):
        """
        Allow relations if a model in the auth app is involved.
        """
        if obj1._meta.app_label == 'auth' or \
         obj2._meta.app_label == 'auth':
         return True
        return None

    def allow_migrate(self, db, model):
        """
        Make sure the auth app only appears in the 'auth'
        database.
        """
        return False
        if db == 'intern_db':
            return (model._meta.app_label == 'auth')
        elif model._meta.app_label == 'auth':
            return False
        return None

错误：

$> ./manage.py migrate
Operations to perform:
  Apply all migrations: contenttypes, admin, auth, sessions
Running migrations:
  Applying contenttypes.0001_initial... OK
  Applying auth.0001_initial... OK
  Applying admin.0001_initial...Traceback (most recent call last):
  File "/usr/lib/python3.4/site-packages/mysql/connector/django/base.py", line 115, in _execute_wrapper
    return method(query, args)
  File "/usr/lib/python3.4/site-packages/mysql/connector/cursor.py", line 507, in execute
    self._handle_result(self._connection.cmd_query(stmt))
  File "/usr/lib/python3.4/site-packages/mysql/connector/connection.py", line 722, in cmd_query
    result = self._handle_result(self._send_cmd(ServerCmd.QUERY, query))
  File "/usr/lib/python3.4/site-packages/mysql/connector/connection.py", line 640, in _handle_result
    raise errors.get_exception(packet)
mysql.connector.errors.DatabaseError: 1005 (HY000): Can't create table `carton2`.`#sql-c20_10d` (errno: 150 "Foreign key constraint is incorrectly formed")

Answer 1

如上所述，您必须通过--database选项来选择数据库。

实际上，将django表放在另一个数据库中而不是默认值是不错的选择，因为其他应用程序假设这些表是默认的。此外，还有一个＆＃34;迁移＆＃34;表自动创建django所需的表。

django multi db change db of intern models

1 个答案: