Question

List<Person> persons = new List<Person>(); 
persons.Add(new Person(){Id = 0, 
                         Birthday = DateTime.Now, 
                         Name="Jack"});            
persons.Add(new Person(){Id = 1, 
                         Birthday = DateTime.Now, 
                         Name = "Anna"});  
persons.Add(new Person(){Id = 2, 
                         Birthday =  DateTime.Now, 
                         Name = "John"});
persons.Add(new Person(){Id = 3, 
                         Birthday = DateTime.Now, 
                         Name = "Sally"}); 
persons.Add(new Person(){Id = 4, 
                         Birthday = DateTime.Now, 
                         Name = "Robert"});

objectListView1.SetObjects(persons);

我想要做的是将对象列表视图中的排序值复制到文本框，其显示顺序与显示的顺序相同，但它们的显示顺序与添加的顺序相同列表＆＃34;人员＆＃34;。

  private void button1_Click(object sender, EventArgs e)
  {
    textBox1.Clear();
    foreach (var person in objectListView1.Objects)
    {
       Person p = person as Person;
       textBox1.Text += p.Id + "\t" + p.Name + "\t" + p.Birthday.ToShortDateString()  + "\r\n";
    }
  }

这是显示当前问题的示例应用的几张图片： Picture 1 Picture2

有没有人知道怎么做？

编辑：我在这个项目中使用了dll： www.codeproject.com/Articles/16009/A-Much-Easier-to-Use-ListView

Answer 1

列表按照添加项目的顺序排序。我猜测显示器是按名称排序的。您可以通过获取最后一个排序列，以与显示它们相同的方式对它们进行排序。我认为我有正确的属性来获取列的名称/顺序。

  private void button1_Click(object sender, EventArgs e)
  {
    textBox1.Clear();

    List<Person> people = objectListView1.Objects.Cast<Person>().ToList();

    if (objectListView1.LastSortColumn != null)
    {
        // check to see if this "Name" property is the right one
        switch (objectListView1.LastSortColumn.Name)
        {
            case "Name":
                if (objectListView1.LastSortOrder == SortOrder.Descending)
                    people = people. OrderByDescending(o => o.Name).ToList();
                else
                    people = people.OrderBy(o => o.Name).ToList();
                break;                                                   
            case "Id":
                if (objectListView1.LastSortOrder == SortOrder.Descending)
                    people = people. OrderByDescending(o => o.Id).ToList();
                else
                    people = people.OrderBy(o => o.Id).ToList();
                break;
            default:
                break;
        }
    }

    foreach (var person in people)
    {
       Person p = person as Person;
       textBox1.Text += p.Id + "\t" + p.Name + "\t" + p.Birthday.ToShortDateString()  + "\r\n";
    }
  }

Answer 2

迟到总比没有好：我认为这更可靠：

const joe = {    // (A) joe is an object
  id: 42,
  name: 'joe',
  hobbies: [     // (B) hobbies is an Array, a reference type
    'surfing',
    'videogames'
  ]
}

// (C) this variable has no idea that it is part of person object from (A)
const cloneHobbies = joe.hobbies
cloneHobbies.push('boxing') 

console.log('***JOE***', joe) // Joe now has a new hobby: boxing

// It also works the other way; Joe's hobbies become someone else's 
joe.hobbies.push('karate')

console.log("***CLONE'S HOBBIES***", cloneHobbies) // now has 'karate'

如果无法转换其所有列表项，则仅返回一个空列表。

对象列表查看如何按显示的顺序复制值

2 个答案: