Question

此任务的目标是找到满足以下所有要求的集合X：

X = {x | x∈Z且x> 0}。



A = {（x mod 2）| x∈X}


B = {y | sqrt（y）∈X}

C = {sqrt（z）| z∈（X∩B）}

D = {w ^ 2 | w∈C}



0＆lt; | X |



| X | ∈X。



| A | （不是元素） X。



sum（X）∈B。



sum（X∩B）6 （不是元素） B。



sum（C∪D）∈X。

所以这就是我试图解决的问题。

我尝试用手解决这个问题，发现X = {6,36,31,33,11,4}是一个符合要求的集合。我也用Python编写了代码，但我的代码不起作用。我没有收到任何错误消息，它只是输出了一个满足要求的集合。这是我用Python编写的代码：

import random
import math

def check(t):

    X1 = t
    X = set([x for x in X1 if x>0])
    A = set([x%2 for x in X]) - set([0])
    print "A= ", "\t", A
    B = set([math.pow(y,2) for y in X ])
    print "B= ", "\t", B
    C = set([math.pow(z, 0.5) for z in X.intersection(B)])
    print "C= ", "\t", C
    D = set([math.pow(w, 2) for w in C])
    print "D= ", "\t", D, "\n"

    #                 (iii)
    if len(X) >0:
        print "iii.\t The cardinality of X bigger than 0." 

    #                 (iv)
    if len(X) in X:
        print "iv.\t\t The cardinality of X is element in X" 

    #                  (v)
    if len(A) not in X:
        print "v.\t\t Cardinality of A is not element in X."

    #                  (vi)
    if sum(X) in B:
        print "vi.\t\t Sum of X is element in B."

    #   (vii)
    if sum(X) and sum(B) not in X:
        print "vii.\t Sum of X and B is not element in B"

    #        (viii)
    if sum(C) in X or sum(D) in X:
        print "viii.\t Sum of C exits in X."


    if len(X)>0 and len(X) in X and len(A) not in X and sum(X) in B and sum(X) not in B and sum(B) not in B and sum(C) in X or sum(D) in X:
        print "Set X is ","\t\t ", X
        print "Fits the requirements."
       # print "A = ", A
    else:
        print "Does not fit the requirements."



def guess():
    b = 20
    genSet = random.sample( range(2,b), 6 )
    t = set(genSet)
    print "---------------"
    print "Generated set is: ", t
    return check(t)



counter=1
while not guess():

    print "try nr: ", teller
    counter+=1

正如您可能已经注意到我刚刚假设该设置为长度= 6，但这只是暂时的，因为我试图让代码工作。由于同样的原因，我的随机数范围并不大。

我还在其间写了一些if / else语句，以检查是否满足要求。

Answer 1

忽略我的评论：不知道我在想什么。只需设置

A = set([x%2 for x in X])

并确保return来自您的函数check：

    ...
    print "Fits the requirements."
    # print "A = ", A
    return True
else:
    print "Does not fit the requirements."
    return False
...

您需要在比较中获得正确的逻辑（长if语句）：

import random
import math

def check(t):

    X1 = t
    X = set([x for x in X1 if x>0])
    A = set([x%2 for x in X])
    print "A= ", "\t", A
    B = set([math.pow(y,2) for y in X ])
    print "B= ", "\t", B
    C = set([math.pow(z, 0.5) for z in X.intersection(B)])
    print "C= ", "\t", C
    D = set([math.pow(w, 2) for w in C])
    print "D= ", "\t", D, "\n"

    #                 (iii)
    if len(X) >0:
        print "iii.\t The cardinality of X bigger than 0." 

    #                 (iv)
    if len(X) in X:
        print "iv.\t\t The cardinality of X is element in X" 

    #                  (v)
    if len(A) not in X:
        print "v.\t\t Cardinality of A is not element in X."

    #                  (vi)
    print '(vi)', sum(X), B
    if sum(X) in B:
        print "vi.\t\t Sum of X is element in B."

    #   (vii)
    if sum(X) and sum(B) not in X:
        print "vii.\t Sum of X and B is not element in B"

    #        (viii)
    if sum(C) in X or sum(D) in X:
        print "viii.\t Sum of C exits in X."


    if len(X)>0 and len(X) in X and len(A) not in X and sum(X) in B and sum(X.intersection(B)) not in B and sum(C.union(D)) in X:
        print "Set X is ","\t\t ", X
        print "Fits the requirements."
       # print "A = ", A
        return True
    else:
        print "Does not fit the requirements."
        return False



def guess():
    b = 20
    genSet = random.sample( range(1,b), 6 )
    t = set(genSet)
    print "---------------"
    print "Generated set is: ", t
    return check(t)

通过这些修改，一个解决方案似乎是{1, 3, 4, 6, 9, 13}。

如何编写满足此集合所有要求的代码？

1 个答案: