Question

我试图在同一个日历月内显示一个帐户列表，其中2个相同的产品已经为同一帐户订购。

字段名称：

A/c number,
Order id,
Cust name,
Product,
Purchase date

我使用过GROUP BY和HAVING，但我关注的是返回的记录量。

Answer 1

SELECT * 
FROM TABLE as table2 
INNER JOIN table as table1 
on table1.product = table2.product AND MONTH(table1.purchase_date) = MONTH(tabl2.purchase_date) AND YEAR(table1.purchase_date) = YEAR(table2.purchase_date)

这应该可以解决问题。

Answer 2

假设我们没有table names，并且缺少数据，这里是一个返回所需内容的查询示例。只需将字段/表名更改为您正在使用的任何名称。

SELECT account_name
  FROM purchaseTable
  JOIN productTable on purchaseTable.product = productTable.id
  WHERE MONTH(purchaseTable.purchase_date) = MONTH(productTable.purchase_date)
  AND YEAR(purchaseTable.purchase_date) = YEAR(productTable.purchase_date)
  HAVING COUNT(*) = 2
  GROUP BY account_name;

Answer 3

我建议两次在同一个表上进行内连接。类似的东西：

SELECT o1.*
FROM orders o1
INNER JOIN orders o2
    ON o1.account_num = o2.account_num
    AND o1.product_id = o2.product_id
    AND MONTH(o1.purchase_date) = MONTH(o2.purchase_date)
    AND YEAR(o1.purchase_date) = YEAR(o2.purchase_date)

我只是想指出，您必须同时匹配月份和年份，以避免将2014年1月购买的物品与2015年1月份相匹配

Answer 4

select *
from accounts
where account_id in (
    select o.account_id
    from orders as o inner join line_items as li on li.order_id = o.order_id
    group by o.account_id, li.product_id, year(o.purchase_date), month(o.purchase_date)
    having count(*) = 2
)

虽然您丢失了购买信息，但很容易获得帐户信息。

这是一种方法，可以将信息与order_ids和订单的日历月保持一致：

select *
from
    accounts as a inner join
    (
    select
        o.account_id, li.product_id,
        year(o.purchase_date) as purchase_yr, month(o.purchase_date) as purchase_mo,
        min(o.order_id) as order_id1, max(o.order_id) as order_id2
    from orders as o inner join line_items as li on li.order_id = o.order_id
    group by o.account_id, li.product_id, year(o.purchase_date), month(o.purchase_date)
    having count(*) = 2
    ) as multiples
        on multiples.account_id = a.account_id

SQL - 根据多个条件检索数据

4 个答案: