Question

所以，基本上，我将有一个名为＆＃34; data.txt＆＃34;

的文件

此文件将包含：

Name;Age;State

示例：

Anne;19;S (Single/Married/etc)
Gustav;18;S
Dinisio;19;C

基本上，我想读取文件，将信息放入数组，并显示/列出它，例如：

Name: Anne
Age: 19
State: S

Name: Gustav
Age: 18
State: S

Name: Dinisio
Age: 19
State: C

为此我创建了一个具有以下结构的类：

    class Person {
    String name;
    int age;
    char state;
    }

变量：

    int i, option;
    String s;
    File f = new File("C:\\Users\\Gustavo\\Desktop\\data.txt");

    Person arrayPerson[] = new Person[4]; // It has 4 persons only

我有以下菜单：

    System.out.print("Choose an option: ");
    System.out.println("\n1- Load");
    System.out.println("2- List");
    System.out.print("Option: ");
    option= ler.nextInt();
    System.out.println("");

    switch(option)
    {
        case 1:
        {
            Exercicio07Java.openRead(f);
            while((s = Exercicio07Java.readLine()) != null)
            {
                String[] str = s.split(";");
                arrayPerson[i] = new Person();
                arrayPerson[i].name = str[0];
                arrayPerson[i].age = Integer.valueOf(str[1]);
                arrayPerson[i].state = str[2].charAt(0);
                i++;
            }
            Exercicio07Java.closeRead();
            break;
        }

        case 2:
        {
            for(i = 0; i < 4; i++)
            {
                System.out.println(arrayPerson[i].nome);
                System.out.println(arrayPerson[i].idade);
                System.out.println(arrayPerson[i].estado);
            }
            break;
        }
    }

我或多或少知道如何阅读信息，但我不知道如何将其传递到数组中，而它被 ;

有什么想法吗？

Answer 1

所以说如果你有四行，你可以这样做：

int index = 0;
while//read line in a file {
    String[] str = lineFromFile.split(";");//will split line on semicolon and you have name in index 0 of array, age in index 1 of str array and so on
    //validate you have all three parameters that you need to create person object.
    Person person = new Person(str[0], convertToInt(str[1]), str[2].charAt(0));//assuming you have constructor that accepts name, converted method to convert age to integer, state
    arrayPerson[index++]=person;
}

Answer 2

使用String.Split（String delimiter）返回String []。如果您将整行读作字符串并创建新人。见下文。这可能是一个寻找你的好地方。

for(int i = 0; i < persons.size(); i++) {
     String [] info = /**Line From File Here As A String*/.split(";");
     persons[i].name = info[0];
     persons[i].age = info[1];
     persons[i].state = info[2];
}

Answer 3

你可以使用bufferedreader进行读取和分割;标记在此之后设置arrayproperty像 arrayPerso [i] .name = temp [0] //这里temp是为分割值存储生成的字符串数组

读取.text信息并将其加载到数组中

3 个答案: