coredata keypath nameOfMovie未在实体中找到<nssqlentity theatres =“”id =“3”> </nssqlentity>

Question

我有一个coredata项目，我正在尝试进行查询。这是我的coredata模型：

NSManagedObjectContext *moc = [self managedObjectContext];
    NSEntityDescription *theaterDescription = [ NSEntityDescription entityForName:@"Theaters" inManagedObjectContext:moc];

     NSPredicate *theaterPredicate = [NSPredicate predicateWithFormat:@"nameOfTheater like %@ AND nameOfMovie like %@",_theaterName,_movieOutlet.stringValue];


    NSFetchRequest *theaterRequestTwo = [NSFetchRequest new];
    theaterRequestTwo.entity = theaterDescription;
    theaterRequestTwo.predicate = theaterPredicate;



    NSError *error = nil;

    NSArray *theaterResults = [moc executeFetchRequest:theaterRequestTwo error:&error];

但是我收到了这个错误：

keypath nameOfMovie not found in entity <NSSQLEntity Theaters id=3>

我也尝试过：

NSPredicate *theaterPredicate = [NSPredicate predicateWithFormat:@"nameOfTheater like %@ AND Movies.nameOfMovie like %@",_theaterName,_movieOutlet.stringValue];

但我收到了这个错误：

keypath Movies.nameOfMovie not found in entity <NSSQLEntity Theaters id=3>

我也尝试过：

NSPredicate *theaterPredicate = [NSPredicate predicateWithFormat:@"nameOfTheater like %@ AND movies.nameOfMovie like %@",_theaterName,_movieOutlet.stringValue];

我收到以下错误：

这里不允许使用多个键

任何人都知道我做错了什么或者我的代码中缺少什么。我非常感谢你的帮助。

更新

这是我的coredata模型的头文件：

剧院classe：

@class Movies;

@interface Theaters : NSManagedObject

@property (nonatomic, retain) NSString * nameOfTheater;
@property (nonatomic, retain) NSSet *movies;
@end

@interface Theaters (CoreDataGeneratedAccessors)

- (void)addMoviesObject:(Movies *)value;
- (void)removeMoviesObject:(Movies *)value;
- (void)addMovies:(NSSet *)values;
- (void)removeMovies:(NSSet *)values;

---

电影课程：

@class Schedules, Theaters;

@interface Movies : NSManagedObject

@property (nonatomic, retain) NSString * nameOfMovie;
@property (nonatomic, retain) NSSet *showTimes;
@property (nonatomic, retain) Theaters *theaters;
@end

@interface Movies (CoreDataGeneratedAccessors)

- (void)addShowTimesObject:(Schedules *)value;
- (void)removeShowTimesObject:(Schedules *)value;
- (void)addShowTimes:(NSSet *)values;
- (void)removeShowTimes:(NSSet *)values;

---

计划课程：

@interface Schedules : NSManagedObject

@property (nonatomic, retain) NSDate * showTimes;
@property (nonatomic, retain) NSSet *movie;
@end

@interface Schedules (CoreDataGeneratedAccessors)

- (void)addMovieObject:(Movies *)value;
- (void)removeMovieObject:(Movies *)value;
- (void)addMovie:(NSSet *)values;
- (void)removeMovie:(NSSet *)values;

Answer 1

您可以使用SUBQUERY来解决此类问题

一个精确的剧院实体（由你的例子复制）

NSPredicate *predicate = [NSPredicate predicateWithFormat:@"nameOfTheater like %@ AND SUBQUERY(movies, $mv, $mv.nameOfMovie like %@).@count > 0", _theaterName,_movieOutlet.stringValue];

<强>更新

电影abc正在运行的所有影院

NSPredicate *predicate = [NSPredicate predicateWithFormat:@"SUBQUERY(movies, $mv, $mv.nameOfMovie CONTAINS[c] %@).@count > 0", @"abc"];

顺便问一下，你的模特是正确的吗？

Theaters <->> Movies = 1:n

所以每个Theater都有x Movies，但Movie只在一个Theater中运行 所以如果你拿一个名字为Movie＆＃34; abc＆＃34;你可以得到Theater作为attibute。或者是

Theaters <<->> Movies = n:m

？因此movies和movieTheaters为NSSet<Movie>/NSSet<Theater>

更新2

仍需要上述问题的答案。什么是正确的关系？是x影院的一部电影或只有一部。你的ManagedObject类的头文件怎么样？ ;）

NSEntityDescription *schedulesDescription = [NSEntityDescription entityForName:@"Schedules" inManagedObjectContext:moc];

// something like this if 1:n. Try and post logs, have no IDE at the moment
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"movie.nameOfMovie == %@ AND movie.movieTheaters.nameOfTheater == %@", @"movie8", @"theaterOne"];

// if n:m, as far as I remember you couldn't fetch over 2 n:m relations via .
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"movie.nameOfMovie == %@ AND SUBQUERY(movie, $mv, $mv.movieTheaters.nameOfTheater == %@).@count > 0", @"movie8", @"theaterOne"];