Question

如何跳过在我的情况下插入重复相同的数组项值？我知道有内置函数，如数组唯一，但我的情况是不同的。

下面代码生成12345555555667，但我只想要1234567，意味着不是重复的值。

$NumArray = array('1','2','3','4','5','5','5','5','5','5','5','6','6','7');
$SecondArray = array();

foreach($NumArray as $num){
    $SecondArray[] = array(
    'alpa'=>$num
    );
}

echo json_encode($SecondArray);

Answer 1

如果$NumArray是静态的，那就像做：

一样简单

foreach (array_unique($NumArray) as $num)
{
    //same code as before
}

但鉴于事实并非如此，你可以写下：

$SecondArray = ();
foreach ($NumArray as $num)
{
    if (!isset($SecondArray[$num]))
    {//key does not exist (yet)
        $SecondArray[$num] = array('alpa' => $num);
    }
}
echo json_encode(array_values($SecondArray));//remove keys, to ensure a JSON array

see the docs

array_values调用确保生成的JSON字符串是JS数组，而不是对象。例如，如果$num为1, 2, 3，则没有 array_values的JSON字符串将如下所示：

{ 1: {alpha: 1}, 2: {alpha: 2}, 3: {alpha: 3} }

使用调用，它看起来像这样：

[ {alpha: 1}, {alpha: 2}, {alpha: 3} ]

Answer 2

怎么样：

$NumArray = array('1','2','3','4','5','5','5','5','5','5','5','6','6','7');
$SecondArray = array();
foreach($NumArray as $key => $value){
    if(in_array($value, $NumArray){
         array_push($SecondArray, $value);
    }
}
echo json_encode($SecondArray);

Answer 3

创建一个新数组，然后循环$NumArray以检查该值是否已存在...如果不存在，则将其添加到新数组中。

<?php
$NumArray = array('1','2','3','4','5','5','5','5','5','5','5','6','6','7');

$newArray = array();
foreach( $NumArray as $val ) {
    if( !in_array( $val, $newArray ) ) {
        $newArray[] = $val;
    }
}
echo '<pre>';
print_r( $newArray );
echo '</pre>';
?>

循环并插入另一个没有冗余的数组

3 个答案: