Question

您好我写了以下代码

PHP

<?php
    try{$bdd = new PDO('mysql:host=localhost;dbname=test', 'root', '');}
    catch (Exception $e){die('Error: ' . $e->getMessage());}

    $req = $bdd->prepare('insert into signup    
           (email,   password,   service,    phone) 
    values(:email,  :password,  :service,   :phone_number)  ');

    $req->execute(array(
    'email'        => htmlspecialchars($_POST['email']),
    'password'     => htmlspecialchars($_POST['password']),
    'service'      => htmlspecialchars($_POST['service']),
    'phone_number' => htmlspecialchars($_POST['phone_number'])));

    echo 'Well done';
    print_r($_POST);

?>

我有一个“做得好”的消息和

     Array ( [email] => test@test.test [password] => test[confirm_password] => test[service] => pizza [phone_number] => 01234 )

当我执行我的代码时。但我的数据库中没有任何东我的错误在哪里？

Answer 1

如果连接失败，则只捕获异常，而不是在使用execute实际插入时捕获异常。要么使用两个@ try / catch，要么扩大try＆amp;的范围。移动你的渔获。

<?php
    try
       {
          $bdd = new PDO('mysql:host=localhost;dbname=test', 'root', '');

          $req = $bdd->prepare('insert into signup    
                 (email,   password,   service,    phone) 
          values(:email,  :password,  :service,   :phone_number)  ');

          $req->execute(array(
          'email'        => htmlspecialchars($_POST['email']),
          'password'     => htmlspecialchars($_POST['password']),
          'service'      => htmlspecialchars($_POST['service']),
          'phone_number' => htmlspecialchars($_POST['phone_number'])));

          echo 'Well done';
          print_r($_POST);
       }

    catch (Exception $e)
    {
         die('Error: ' . $e->getMessage());
    }

?>

数据未存储在数据库中但没有错误

1 个答案: