我正在寻找一种方法连续播放2个视频而没有任何延迟(或者
更换文件时非常小的延迟
我有1 mp4文件和ffmpeg我把它分成2个文件,现在我想要
将它们添加到播放列表中并播放它们但我不想要用户感觉
改变视频但是当我因为加载文件而测试时有一个
延迟。
我想在第一个文件结束之前将第二个文件串流到内存中。
我怎么能这样做?
我测试了LibVLC并阅读Play a Video from MemoryStream, Using FFMpeg但仍然没有运气
PS:任何语言的图书馆对我都有好处。
编辑:文件很小(小于5mb且小于5秒)。
编辑:我在FreePascal中添加了一个带有PasLibVLC的演示,它在第一个文件之后播放第二个文件,但是有一个延迟beetwen正在改变。如何最小化这个?(例如从内存中加载VLC并加载第二个文件到内存中)。
unit MainFormUnit;
{$mode Delphi}{$H+}
interface
uses
Classes, SysUtils, FileUtil, Forms, Controls, Graphics, Dialogs, Menus,LCLIntf, LCLType,
ExtCtrls, StdCtrls,PasLibVlcUnit,PasLibVlcPlayerUnit;
const
MAX_ARGS = 255;
type
{ TMainForm }
TMainForm = class(TForm)
Button1: TButton;
MenuFile: TMenuItem;
MenuFileOpen: TMenuItem;
MenuFileQuit: TMenuItem;
Panel1: TPanel;
Panel2: TPanel;
procedure Button1Click(Sender: TObject);
procedure FormCreate(Sender: TObject);
procedure FormDestroy(Sender: TObject);
private
p_li: libvlc_instance_t_ptr;
p_mi: libvlc_media_player_t_ptr;
argv: packed array[0..MAX_ARGS - 1] of ansistring;
args: packed array[0..MAX_ARGS - 1] of PAnsiChar;
argc: integer;
p_mi_ev_mgr: libvlc_event_manager_t_ptr;
procedure AddArg(Value: ansistring);
procedure PlayerInit();
procedure PlayerPlay(fileName: WideString);
procedure PlayerStop();
procedure PlayerDestroy();
procedure WmMediaPlayerEndReached(var m: TVlcMessage); message WM_MEDIA_PLAYER_END_REACHED;
public
{ Public declarations }
end;
var
MainForm: TMainForm;
procedure lib_vlc_player_event_hdlr(p_event: libvlc_event_t_ptr; Data: Pointer); cdecl;
implementation
{$R *.lfm}
procedure lib_vlc_player_event_hdlr(p_event: libvlc_event_t_ptr; Data: Pointer); cdecl;
var
Form: TMainForm;
begin
if (Data = nil) then
exit;
Form := TMainForm(Data);
if not Assigned(Form) then
exit;
case p_event^.event_type of
libvlc_MediaPlayerEndReached:
PostMessage(Form.Handle, WM_MEDIA_PLAYER_END_REACHED, WPARAM(0), LPARAM(0));
end;
end;
{ TMainForm }
procedure TMainForm.AddArg(Value: ansistring);
begin
if (argc < MAX_ARGS) then
begin
argv[argc] := Value;
args[argc] := PAnsiChar(argv[argc]);
Inc(argc);
end;
end;
procedure TMainForm.PlayerInit();
begin
libvlc_dynamic_dll_init();
if (libvlc_dynamic_dll_error <> '') then
begin
MessageDlg(libvlc_dynamic_dll_error, mtError, [mbOK], 0);
exit;
end;
argc := 0;
AddArg(libvlc_dynamic_dll_path);
AddArg('--intf=dummy');
AddArg('--ignore-config');
AddArg('--quiet');
AddArg('--no-video-title-show');
AddArg('--no-video-on-top');
p_li := libvlc_new(argc, @args);
p_mi := nil;
end;
procedure TMainForm.PlayerPlay(fileName: WideString);
var
p_md: libvlc_media_t_ptr;
a_st: ansistring;
p_st: PAnsiChar;
begin
PlayerStop();
a_st := UTF8Encode(fileName);
p_st := PAnsiChar(@a_st[1]);
p_md := libvlc_media_new_path(p_li, p_st);
if (p_md <> nil) then
begin
p_mi := libvlc_media_player_new_from_media(p_md);
if (p_mi <> nil) then
begin
libvlc_video_set_key_input(p_mi, 1);
libvlc_video_set_mouse_input(p_mi, 1);
libvlc_media_player_set_display_window(p_mi, SELF.Handle);
p_mi_ev_mgr := libvlc_media_player_event_manager(p_mi);
libvlc_event_attach(p_mi_ev_mgr, libvlc_MediaPlayerEndReached, @lib_vlc_player_event_hdlr, SELF);
end;
libvlc_media_player_play(p_mi);
libvlc_media_release(p_md);
end;
end;
procedure TMainForm.PlayerStop();
begin
if (p_mi <> nil) then
begin
libvlc_media_player_stop(p_mi);
while (libvlc_media_player_get_state(p_mi) = libvlc_Playing) do
begin
Sleep(50);
end;
libvlc_media_player_release(p_mi);
p_mi := nil;
end;
end;
procedure TMainForm.PlayerDestroy();
begin
if (p_li <> nil) then
begin
PlayerStop();
libvlc_release(p_li);
p_li := nil;
end;
end;
procedure TMainForm.WmMediaPlayerEndReached(var m: TVlcMessage);
begin
PlayerPlay('C:\ffmpeg\bin\tmp\OUTPUT1.mp4');
end;
procedure TMainForm.FormCreate(Sender: TObject);
begin
p_li := nil;
p_mi := nil;
PlayerInit();
Button1.Click;
end;
procedure TMainForm.Button1Click(Sender: TObject);
begin
PlayerPlay('C:\ffmpeg\bin\tmp\OUTPUT0.mp4');
end;
procedure TMainForm.FormDestroy(Sender: TObject);
begin
PlayerDestroy();
end;
end.
答案 0 :(得分:0)
HTML5媒体源扩展(MSE)应该允许你这样做,但它很棘手,因为你必须自己处理视频的流媒体和缓冲。如果你能找到一个内置功能的媒体播放器就会容易得多。请点击此处查看更多信息和MSE链接以回答类似问题: