Question

我的测试中有问题。所以我有这样的情景：

Scenario: Teste la route /settlement/rank/types
Given I request "http:/localhost/admin"
Then  the response should be JSON
And   I should have code with value 200
And   I should have error with value 0
And   The response has a "aUser" property
And   This property "aUser" is not empty
And   The property "aUser" has the keys:
          |id_user |login |first_name |last_name |email |id_company |enable |id_language |label_language |

现在FeatureContext是：

/**
 * @Given /^The property "([^"]*)" has the keys:$/
 */
public function thePropertyHasTheKeys($aProperty, TableNode $table){
    $data = json_decode($this->_response->getBody(true),true);
    foreach($table as $value){
        print_r($value['id_user']);
        if(!in_array($value,$data['data'][$aProperty])){
            throw new Exception("The property ".$value. " is not set\n");
        }
    }
}

在$data我有一个这种形式的数组：

|id_user |login |first_name |last_name |email |id_company |enable |id_language |label_language |

所以我想比较数组$data和数组$table，如果键是相同的。

Answer 1

或许这样的事情？

$data = json_decode($this->_response->getBody(true),true);
foreach($table as $key=>$value)
{

    if( !isset($data[$key]) ) { throw new Exception("The key ".$key. " is not set\n"); }
    if( $data[$key]!=$value ) { throw new Exception("The value ".$value. " is wrong\n"); }
}

Answer 2

我喜欢重复使用其他人的代码，使其更加明显 - 在这种情况下，PHPunit可以很好地处理很多事情：

// outside the test class
require_once 'PHPUnit/Framework/Assert/Functions.php';

// convert $table to a clean array ....

// compare
$data = json_decode($this->_response->getBody(true), true);
assertEquals($table, $data, 'Decoded JSON does not match the given example');

如何验证密钥是否在Behat中的数组中

2 个答案: