Question

我希望通过我的计算机主机（服务器）和Raspberry pi板（客户端）之间的套接字进行通信。我使用以下代码：

对于服务器

 public void startApp() {
        try
    {
 ServerSocketConnection ssc = (ServerSocketConnection) 
  Connector.open("socket://:9002");
  StreamConnection sc = null;
  InputStream is = null;
  try{
    sc = ssc.acceptAndOpen();
    is = sc.openInputStream();
    int ch = 0;
    StringBuffer sb = new StringBuffer();
    while ((ch = is.read()) != -1){
      sb.append((char)ch);
    }
    System.out.println(sb.toString());
  } finally{
      ssc.close();
      sc.close();
      is.close();
  }
} catch (IOException x) {
    x.printStackTrace();
}


    }

对于客户

           try{
  SocketConnection sc = (SocketConnection) 
    Connector.open("socket://10.91.40.145:9002");
  OutputStream os = null;
  try{
    os = sc.openOutputStream();
    byte[] data = "Hello from a socket!".getBytes();
    os.write(data);
  } finally{
      sc.close();
      os.close();
  }
} catch (IOException x){
    x.printStackTrace();
}

当我在Raspberry pi上运行客户端时，我得到了以下日志：

Java is starting. Press Ctrl-C to exit
[CRITICAL] [SECURITY] iso=2:Permission check failed: javax.microedition.io.SocketProtocolPermission "socket://10.91.40.145:9002" ""
TRACE: <at java.security.AccessControlException: >, startApp threw an Exception
java.security.AccessControlException: 
 - com/oracle/meep/security/AccessControllerInternal.checkPermission(), bci=128
 - java/security/AccessController.checkPermission(), bci=1
 - com/sun/midp/io/j2me/socket/Protocol.open(), bci=127
 - com/sun/midp/io/j2me/socket/Protocol.openPrim(), bci=4
 - javax/microedition/io/Connector.open(), bci=77
 - javax/microedition/io/Connector.open(), bci=6
 - javax/microedition/io/Connector.open(), bci=3
 - smartgridapidemopi/SmartGridAPIdemoPI.startApp(SmartGridAPIdemoPI.java:48)
 - javax/microedition/midlet/MIDletTunnelImpl.callStartApp(), bci=1
 - com/sun/midp/midlet/MIDletPeer.startApp(), bci=5
 - com/sun/midp/midlet/MIDletStateHandler.startSuite(), bci=264
 - com/sun/midp/main/AbstractMIDletSuiteLoader.startSuite(), bci=38
 - com/sun/midp/main/CldcMIDletSuiteLoader.startSuite(), bci=5
 - com/sun/midp/main/AbstractMIDletSuiteLoader.runMIDletSuite(), bci=132
 - com/sun/midp/main/AppIsolateMIDletSuiteLoader.main(), bci=26
java.security.AccessControlException: 
 - com/oracle/meep/security/AccessControllerInternal.checkPermission(), bci=[ERROR] [AMS] iso=1:Sending the notification: com.oracle.midp.proxy.RunCommand@d17b7662. FAILED, proxy is disconnected
128
 - java/security/AccessController.checkPermission(), bci=1
 - com/sun/midp/io/j2me/socket/Protocol.open(), bci=127
 - com/sun/midp/io/j2me/socket/Protocol.openPrim(), bci=4
 - javax/microedition/io/Connector.open(), bci=77
 - javax/microedition/io/Connector.open(), bci=6
 - javax/microedition/io/Connector.open(), bci=3
 - smartgridapidemopi/SmartGridAPIdemoPI.startApp(SmartGridAPIdemoPI.java:48)
 - javax/microedition/midlet/MIDletTunnelImpl.callStartApp(), bci=1
 - com/sun/midp/midlet/MIDletPeer.startApp(), bci=5
 - com/sun/midp/midlet/MIDletStateHandler.startSuite(), bci=264
 - com/sun/midp/main/AbstractMIDletSuiteLoader.startSuite(), bci=38
 - com/sun/midp/main/CldcMIDletSuiteLoader.startSuite(), bci=5
 - com/sun/midp/main/AbstractMIDletSuiteLoader.runMIDletSuite(), bci=132
 - com/sun/midp/main/AppIsolateMIDletSuiteLoader.main(), bci=26
[ERROR] [AMS] iso=1:Sending the notification: com.oracle.midp.proxy.RunCommand@d17b76f0. FAILED, proxy is disconnected
[ERROR] [AMS] iso=1:Sending the notification: com.oracle.midp.proxy.StopCommand@d17b76ff. FAILED, proxy is disconnected

如何处理此AccessControlException。??

Answer 1

端口9002被防火墙或防病毒软件关闭。检查端口可用性。

Answer 2

提供API权限 javax.microedition.io.SocketProtocolPermission（“套接字：// ：”） javax.microedition.io.SocketProtocolPermission（“套接字：//：*”）

你的jad文件中的

您可以通过导航项目属性 - ＆gt;在netbeans中执行此操作。应用描述符选择API Permission选项卡。

J2ME Socket程序中的权限检查失败

2 个答案: