Question

我有一个简单的脚本，目前向3个人发送电子邮件。

如果我直接转到网址，脚本会正常工作（它会发送电子邮件）。

但是，如果我将其设置为cpanel中的cron作业，当cron作业触发时，我会通知我的cron电子邮件：

/home/ultranet/public_html/newsletter/blast_script.php: line 1: ?php: No such file or directory
/home/ultranet/public_html/newsletter/blast_script.php: line 2: /*: No such file or directory
/home/ultranet/public_html/newsletter/blast_script.php: line 3: Script: command not found
/home/ultranet/public_html/newsletter/blast_script.php: line 4: January: command not found
/home/ultranet/public_html/newsletter/blast_script.php: line 5: Please: command not found
/home/ultranet/public_html/newsletter/blast_script.php: line 6: ----------------------------------------------------------------------: command not found
/home/ultranet/public_html/newsletter/blast_script.php: line 7: include_once: command not found
/home/ultranet/public_html/newsletter/blast_script.php: line 8: syntax error near unexpected token `('
/home/ultranet/public_html/newsletter/blast_script.php: line 8: `$sql = mysql_query("SELECT * FROM newsletter WHERE received='1' LIMIT 20");'

，脚本是：

<?php
/* -------------------------------------------------------------------
Script written by Adam Khoury @ www.developphp.com
                          January 1, 2010
Please retain this credit when displaying this code online 
---------------------------------------------------------------------- */
include_once "connect_to_mysql.php";
$sql = mysql_query("SELECT * FROM newsletter WHERE received='1' LIMIT 20");
$numRows = mysql_num_rows($sql); // Added for "End Campaign Check" at the bottom of this file(not shown on the video)
$mail_body = '';
while($row = mysql_fetch_array($sql)){
    $id = $row["id"];
    $email = $row["email"];
    $name = $row["name"];

    $mail_body = '<html>
<body style="background-color:#CCC; color:#000; font-family: Arial, Helvetica, sans-serif; line-height:1.8em;">
<h3><a href="http://www.developphp.com"><img src="http://www.yoursite.com/images/logo.png" alt="DevelopPHP" width="216" height="36" border="0"></a> Newsletter
</h3>
<p>Hello ' . $name . ',</p>
<p>You can make this out to be just like most any web page or design format you require using HTML and CSS.</p>
<p>~Adam @ DevelopPHP</p>
<hr>
<p>To opt out of receiving this newsletter,  <a href="http://www.developphp.com/Tests/newsletter/optout.php?e=' . $email . '">click here</a> and we will remove you from the listing immediately.</p>
</body>
</html>';
    $subject = "Develop PHP Newsletter";
    $headers  = "From:newsletter@developphp.com\r\n";
    $headers .= "Content-type: text/html\r\n";
    $to = "$email";

    $mail_result = mail($to, $subject, $mail_body, $headers);

    if ($mail_result) {
        // mysql_query("UPDATE newsletter SET received='1' WHERE email='$email' LIMIT 1");
    } else {
       // this else statement can be used to write into an error log if the mail function fails
       // It can also be removed if you do not need error logging
    }

}

// This section is script I discussed adding to this file on video
// This section is for sending the site owner a message informing them that
// all people in the database have been sent the newsletter for the current campaign
if ($numRows == 0) { // $numRows is set on line 4 using the existing query

     $subj = "Newsletter Campaign Has Ended";
     $body = "The current newsletter campaign has ended. All have been sent the newsletter.";
     $hdr  = "From:newsletter@developphp.com\r\n";
     $hdr .= "Content-type: text/html\r\n";
     mail("yourEmailAddressHere", $subj, $body, $hdr);

}
// End Check Section
?>

为什么它会产生错误，因为在url中直接调用脚本时脚本正常工作？

我问了我的主人，但他们不知道问题是什么。

Answer 1

我猜您只是将cronjob的命令设置为/path/to/your/script.php，但此脚本不是可执行文件。你必须在这个脚本前面添加php解释器，i。即

php /path/to/your/script.php

在cronjob的配置中。

Answer 2

记下命令行

 which php

它将返回文件的路径，可能就像

 /etc/bin/php

而不是直接在cron中调用php，而是将其用作

/etc/bin/php /path/to/script.php

在环境中没有设置Php，这就是为什么cron无法找到php。

Answer 3

您必须在执行php脚本的每一行的开头指定php的路径。例如在crontab中的debian（crontab -e）：

01 00 * * * /usr/bin/php5 /var/www/Projet/script.php

cron job没有解雇工作的php脚本，会产生错误

3 个答案: