Question

代码：

var files = Directory.EnumerateFiles("C:\\coneimages", "*.*", SearchOption.AllDirectories)
    .Where(s => s.EndsWith(".mp3") || s.EndsWith(".gif"));
    foreach (string f in files)
    {
        filesl.Add(f);
    }
    for (int i = 0; i < filesl.Count; i++)
    {
        Bitmap bmp1 = new Bitmap(filesl[i]);
        Bitmap bmp2 = new Bitmap(@"c:\coneimages\PictureBox_Images1.gif");
        Bitmap bmp3 = new Bitmap(GenerateImage(bmp2, bmp1));
        bmp3.Save(@"c:\coneimages\merged.bmp");
    }

文件为IEnumerable<string>，filesl为List<string>

问题在于：Bitmap bmp1 = new Bitmap(filesl[i]);

在此之前：Bitmap bmp1 = Bitmap(@"c:\coneimages\Cone_Images1.gif");

问题是我在List<string>

中有很多文件

列表中的第一个我拥有所有Cone_images文件，例如：

Cone_images1,Con_images2,Con_images3......Con_images360

然后我在同一个列表中：

PictureBox_Images1,PictureBox_Images2....PictureBox_Images360

在循环中我需要做的是每个迭代两个文件并合并它们。例如文件：Con_images1 with PictureBox_Images1 接下来迭代循环中的几个文件：Con_images2 with PictureBox_Images2 .....最后一次迭代将是：Con_images360 with PictureBox_Images360

Answer 1

因此，一种类型的文件名始终以"Cone_images"开头，而另一种始终以"PictureBox_Images"开头，以数字部分结尾？然后我首先将它们分开。最后，您可以在使用数字部分命令它们之后使用Enumerable.Zip：

var allFiles =Directory.EnumerateFiles("C:\\coneimages", "*.*", SearchOption.AllDirectories)
    .Where(s => s.EndsWith(".mp3") || s.EndsWith(".gif"));
var coneFiles = allFiles
    .Where(f => Path.GetFileNameWithoutExtension(f).StartsWith("Cone_images", StringComparison.InvariantCultureIgnoreCase))
    .Select(f => new
    {
        File = f,
        NumberPart = String.Concat(Path.GetFileNameWithoutExtension(f).SkipWhile(c => !char.IsDigit(c)).TakeWhile(char.IsDigit))
    }).Where(x => x.NumberPart.Any())
    .Select(x => new { x.File, Number = int.Parse(x.NumberPart) })
    .OrderBy(x => x.Number);
var pictureBoxFiles = allFiles
     .Where(f => Path.GetFileNameWithoutExtension(f).StartsWith("PictureBox_Images", StringComparison.InvariantCultureIgnoreCase))
    .Select(f => new
    {
        File = f,
        NumberPart = String.Concat(Path.GetFileNameWithoutExtension(f).SkipWhile(c => !char.IsDigit(c)).TakeWhile(char.IsDigit))
    }).Where(x => x.NumberPart.Any())
    .Select(x => new { x.File, Number = int.Parse(x.NumberPart) })
    .OrderBy(x => x.Number);

var bothFileTypes = coneFiles.Zip(pictureBoxFiles, (cone, pic) => new { cone, pic });
foreach (var xy in bothFileTypes)
{
    Bitmap bmp1 = new Bitmap(xy.cone.File);
    Bitmap bmp2 = new Bitmap(xy.pic.File);
    Bitmap bmp3 = new Bitmap(GenerateImage(bmp2, bmp1));
    bmp3.Save(@"c:\coneimages\merged.bmp");
}

这是另一种类似于使用Enumerable.GroupBy的Sayse的方法。它不依赖于订单，也不会压缩可能不属于一起的文件。它按最后的数字分组，并标识每个文件的类型：

string coneIdentifier = "Cone_images";
string picIdentifier = "PictureBox_Images";
var numberGroups = Directory.EnumerateFiles("C:\\coneimages", "*.*", SearchOption.AllDirectories)
    .Where(f => Path.GetExtension(f).Equals(".mp3", StringComparison.InvariantCultureIgnoreCase) || Path.GetExtension(f).Equals(".gif", StringComparison.InvariantCultureIgnoreCase))
    .Select(f => new { File = f, FileName = Path.GetFileNameWithoutExtension(f) })
    .Where(x => x.FileName.StartsWith(coneIdentifier, StringComparison.InvariantCultureIgnoreCase) || x.FileName.StartsWith(picIdentifier, StringComparison.InvariantCultureIgnoreCase))
    .Select(x => new
    {
        x.File,
        x.FileName,
        NumberPart = String.Concat(x.FileName.SkipWhile(c => !char.IsDigit(c)).TakeWhile(char.IsDigit)),
        Type = String.Concat(x.FileName.TakeWhile(c => !char.IsDigit(c)))
    })
    .Where(x => x.NumberPart.Length > 0 && x.Type.Length > 0)
    .GroupBy(x => x.NumberPart);

foreach (var grp in numberGroups)
{
    var cone = grp.FirstOrDefault(x => x.Type.Equals(coneIdentifier, StringComparison.InvariantCultureIgnoreCase));
    var pic = grp.FirstOrDefault(x => x.Type.Equals(picIdentifier, StringComparison.InvariantCultureIgnoreCase));
    if (cone == null || pic == null) continue;
    Bitmap bmp1 = new Bitmap(cone.File);
    Bitmap bmp2 = new Bitmap(pic.File);
    // ...
}

Answer 2

如果您的Cone_images＆amp;的命名PictureBox总是一样的，这可能会有所帮助：

Bitmap bmp1 = new Bitmap(filesl[i]);
string filePictureBox = string.Format(@"c:\coneimages\PictureBox_Images{0}.gif", i);

// check if file exists
if(File.Exists(filePictureBox))
{
    Bitmap bmp2 = new Bitmap(filePictureBox);
    Bitmap bmp3 = new Bitmap(GenerateImage(bmp2, bmp1));
    bmp3.Save(@"c:\coneimages\merged.bmp");
}

如何在每次另一个文件时从List <string>获取文件？</string>

2 个答案: