Question

任何人都可以帮我构建一个oracle查询，以获得低于预期的结果我有2个表，命名为 detention_charge_slot 和 detention_invoice 示例如下

create table detention_charge_slot
        (slot_no number(5),
        from_days number(10),
        to_days number(10),
        charge_amount number(10,2));

insert into detention_charge_slot
        values (1,1,4,0);

        insert into detention_charge_slot
        values (2,5,9,10);

        insert into detention_charge_slot
        values (3,10,14,20);

        insert into detention_charge_slot
        values (4,15,999,25);

create table detention_invoice
        (invoice_no number(10),
        invoice_dt date,
        delivery_dt date);
insert into detention_invoice
        values(1,'10-JAN-2015','25-JAN-2015');

现在我想为invoice_no = 1写一个查询，它会给我以下结果

Start_date | End_date |   Days| Charge_Amount
10-JAN-2015  13-JAN-2015    4      0
14-JAN-2015  18-JAN-2015    5     10
19-JAN-2015  23-JAN-2015    5     20
24-JAN-2015  25-JAN-2015    2     25

Answer 1

SQL查询中的谓词可以基于表达式，例如：

SELECT Charge
FROM   date_range_charge
WHERE  From_days <= (TO_DATE(:param2,'DD-MON-YYYY') 
                     - TO_DATE(:param1,'DD-MON-YYYY') + 1)
AND    To_days   >= (TO_DATE(:param2,'DD-MON-YYYY')
                     - TO_DATE(:param1,'DD-MON-YYYY') + 1);

Answer 2

select invoice_dt + from_days - 1 start_date, 
    invoice_dt + to_days -1 end_date, 
    to_days-from_days + 1 days, charge_amount
  from detention_charge_slot dcs
    join detention_invoice di on (di.invoice_no = 1)
  order by slot_no

result: 
START_DATE  END_DATE   DAYS CHARGE_AMOUNT
2015-01-10  2015-01-13    4          0,00
2015-01-14  2015-01-18    5         10,00
2015-01-19  2015-01-23    5         20,00
2015-01-24  2017-10-04  985         25,00

最后一行是不同的，因为你在detention_charge_slot.to_days中放了999。如果你想要2那么修改查询就像这里：

select invoice_dt + from_days - 1 start_date, 
    least(invoice_dt + to_days - 1, delivery_dt) end_date, 
    least(invoice_dt + to_days - 1, delivery_dt) - (invoice_dt + from_days - 2) days, 
    charge_amount
  from detention_charge_slot dcs
    join detention_invoice di on (di.invoice_no = 1)
  order by slot_no

result: 
START_DATE  END_DATE   DAYS CHARGE_AMOUNT
2015-01-10  2015-01-13    4          0,00
2015-01-14  2015-01-18    5         10,00
2015-01-19  2015-01-23    5         20,00
2015-01-24  2015-01-25    2         25,00

Oracle Query根据日期范围和发票表生成日期和计算费用

2 个答案: