Question

我有一个模型，我正在通过表单向导进行更新。在最后一步，我想用表单数据更新对象，然后在模型中调用回调以将数据推送到外部API。我遇到的问题是finall步骤是将数据保存在两个事务中。

# controller
def update
  @business = current_user
  @loanapplication = @business.loan_applications.last
  @loanapplication.update_attributes(loan_application_params(step))
  params[:loan_application][:status] = 'active' if step == steps.last
  render_wizard @loanapplication
end

# Model
# Callbacks
after_commit :create_salesforce_loan_application, :on => :update
def create_salesforce_loan_application
  if self.status == 'active'
    puts "create salesforce function running"       
    # Updating business column
    self.business.update_column(:state, 1)
  end
end

数据库交易

[paperclip] saving XXX.xlsx
[AWS S3 200 0.101161 0 retries] put_object(:acl=>:public_read,:bucket_name=>"",:content_length=>29467,:content_type=>"application/vnd.openxmlformats-officedocument.spreadsheetml.sheet",:data=>Paperclip::UploadedFileAdapter: FX - Competitive Analysis.xlsx,:key=>"XX.xlsx")  
(0.4ms)  COMMIT
create salesforce function running
SQL (1.3ms)  UPDATE "users" SET "state" = 1 WHERE "users"."type" IN ('Business') AND "users"."id" = 55
(0.2ms)  BEGIN
(0.2ms)  COMMIT
create salesforce function running
SQL (1.3ms)  UPDATE "users" SET "state" = 1 WHERE "users"."type" IN ('Business') AND "users"."id" = 55

这两个提交正在我的模型中进行两次回调，如果我能弄清楚如何保存更新模型中的数据一次，那么我的回调只会触发一次。有没有办法可以找出造成两次提交的原因？

Answer 1

:create_salesforce_loan_application被调用两次，因为对象在此过程中更新了两次，可能是其他回调或宝石，如Paperclip。

更好的方法是使用after_save代替after_commit，检查:status属性是否已更改。

class LoanApplication < ActiveRecord:Base
  after_save :create_salesforce_loan_application, on: :update

  def create_salesforce_loan_application
    if status_changed? && status == 'active'
      puts "create salesforce function running"       
      # Updating business column
      business.update_column(:state, 1)
    end
  end
end

Rails更新对象创建两个数据库事务

1 个答案: