Question

我有一个弹出窗体从用户获取数据并将其添加到MySQL phpmyadmin表中，我希望能够在弹出窗口关闭后在html表格中显示此数据，在我点击提交后我会被定向回到主页，我希望数据显示在桌面上。

M.html

 <thead>    
        <tr>
            <th scope="col" colspan="2">CRN</th>
            <th scope="col" colspan="6">Title</th>
            <th scope="col" rowspan="2">Co-Ordinator</th>
            <th scope="col" colspan="6">Coursework Number</th>
            <th scope="col" rowspan="2">Contribution</th>
            <th scope="col" colspan="6">Edit</th> 
            <th scope="col" rowspan="2">Upload</th>
            <th scope="col" colspan="6">Manage Grades</th>        
        </tr>   

        </table>

add.php

$display_query = "SELECT CRN, Title, Co-Ordinator, CourseworkNumber, Contribution FROM Modules";
$displayresult = mysqli_query($con, $display_query);

$num = mysql_numrows($displayresult);

mysqli_close($con);

header("Location: ../views/M.html");

我是html和php的新手，我不知道如何将其链接到html

Answer 1

您可以通过多种方式实现这一目标。中国牛市的方法是：

<thead>    
    <tr>
        <th scope="col" colspan="2">CRN</th>
        <th scope="col" colspan="6">Title</th>
        <th scope="col" rowspan="2">Co-Ordinator</th>
        <th scope="col" colspan="6">Coursework Number</th>
        <th scope="col" rowspan="2">Contribution</th>
        <th scope="col" colspan="6">Edit</th> 
        <th scope="col" rowspan="2">Upload</th>
        <th scope="col" colspan="6">Manage Grades</th>        
    </tr>   
<?php
    $display_query = "SELECT CRN, Title, Co-Ordinator, CourseworkNumber, Contribution FROM Modules";
    $displayresult = mysqli_query($con, $display_query);

    while($row = mysqli_fetch_assoc($display_query)) { // loop through the returned rows
        // output each elemment
        echo '<tr>';
        echo '<td>'  . $row['CRN'] . '</td>';
        // other column items in the same fashion
        echo '</tr>';
    }

    mysqli_close($con);

?>
</table>

Answer 2

在您的主页上执行提取查询。为此，使M.html到M.php并执行查询以从数据库中获取数据。

<table>
<th> <!--table headers--> </th>
<?php
$query = $con ->query(SELECT * FROM Modules);
while($row = $query->fetch){
echo '<tr>';

echo '<td>'.$row['CRN'].'</td>';
echo '<td>'.$row['Title'].'</td>';
echo '<td>'.$row['Co-Ordinator'].'</td>';
echo '<td>'.$row['CourseworkNumber'].'</td>';
echo '<td>'.$row['Contribution'].'</td>';

echo '</tr>'

}
?>
</table>

PS - 您无法在.html文件中执行PHP代码

使用html表显示MySql数据

2 个答案: