Question

我的列表视图似乎无法在屏幕上显示。

我正在使用tabhost并在一个框架中放置一个列表但由于某种原因它无效。

我确信我的代码看起来是正确的，所以我不确定这里有什么问题..

请帮忙！

这是我的XML：

<?xml version="1.0" encoding="utf-8"?>

<TabHost xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent"
    android:id="@android:id/tabhost">

    <LinearLayout
        android:id="@+id/LinearLayout01"
        android:orientation="vertical"
        android:layout_height="fill_parent"
        android:layout_width="fill_parent">

        <TextView
            android:layout_width="wrap_content"
            android:layout_height="wrap_content"
            android:textAppearance="?android:attr/textAppearanceLarge"
            android:text="List"
            android:id="@+id/listtext"
            android:layout_gravity="center_horizontal" />

        <TabWidget
            android:id="@android:id/tabs"
            android:layout_height="wrap_content"
            android:layout_width="fill_parent">
        </TabWidget>

        <FrameLayout
            android:id="@android:id/tabcontent"
            android:layout_height="fill_parent"
            android:layout_width="fill_parent">

            <ListView
                android:id="@+id/list"
                android:layout_height="0dp"
                android:layout_width="match_parent"
                android:layout_weight="1">
            </ListView>
        </FrameLayout>
    </LinearLayout>

</TabHost>

标签1代码：

public class WorkoutDay1 extends Activity {
    ListView listView ;


    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.workoutlist_main);

        // Get ListView object from xml
        listView = (ListView) findViewById(R.id.list);
        // Defined Array values to show in ListView
        String[] values = new String[] { "Chest Press",
                "Shoulder Press",
                "Arm Extension",
        };

        ArrayAdapter<String> adapter = new ArrayAdapter<String>(this,
                android.R.layout.simple_list_item_1, android.R.id.text1, values);
        // Assign adapter to ListView
        listView.setAdapter(adapter);
        // ListView Item Click Listener
        listView.setOnItemClickListener(new AdapterView.OnItemClickListener() {

            @Override
            public void onItemClick(AdapterView<?> parent, View view,
                                    int position, long id) {

/*                // ListView Clicked item index
                int itemPosition     = position;

                // ListView Clicked item value
                String  itemValue    = (String) listView.getItemAtPosition(position);*/

                // Show Alert
                if(position == 0) {
                    //code specific to first list item
                    Intent myIntent = new Intent(view.getContext(), workout.class);
                    startActivityForResult(myIntent, 0);

                }

                if(position == 1) {
                    //code specific to 2nd list item
                    Toast.makeText(getApplicationContext(),
                            "Coming Soon.", Toast.LENGTH_SHORT)
                            .show();
                }

                if(position == 2) {
                    //code specific to 2nd list item
                    Toast.makeText(getApplicationContext(),
                            "Coming Soon." , Toast.LENGTH_SHORT)
                            .show();
                }

            }

        });




    }

}

Answer 1

您发布了完整的代码，但我猜您在将数据分配到列表后可能没有调用notifyDataSetChanged()。

Android ListView没有出现

1 个答案: