我正在尝试循环变量,搜索ID,然后进行ajax调用以获取Success函数中不同ID的Detailcontent我尝试循环接收的内容并将电子邮件发送出去。
它正在运行,但我在$ scope.subContactmail中收到了第一封电子邮件。我认为循环有问题,但我不明白。试图弄清楚整个晚上,不幸的是没有想法来到低谷。想法应该是,如果第一个循环完成,它将从第二个循环开始。但是目前第一个循环也是第二个循环。
Problaby你的专业人士可以帮助我解决这个问题。
期待您的帮助!
以下是我的角度应用文件的具体部分:
//find all contract relations id's from customer
$scope.contactrelation = function (input) {
$http.post('http://localhost/mamiexpress/mamiAPI/includes/php/searchContactsRelation.php', input).
success(function(data, status, headers, config) {
$scope.subContactDetails = [];
$scope.subContactmail = [];
$scope.subContactId = data;
console.log($scope.subContactId);
//GET ALL the subcontact ID's from the selected item
var i=0;
var subContactIdlenght = $scope.subContactId.length;
while (i < subContactIdlenght) {
console.log($scope.subContactId[i].contact_sub_id);
var number = $scope.subContactId[i].contact_sub_id;
i = i + 1;
//Send the ID to the API and get the user Details
$http.post('http://localhost/mamiexpress/mamiAPI/includes/php/searchContactswithID.php', number).
success(function(data, status, headers, config) {
$scope.subContactDetails.push(data); // store it in subContactDetails
console.log($scope.subContactDetails);
//HERE COULD BE THE PROBLEM!!
// I want this loop to start when the first loop is finished but i have to run this in this success function.
// At the moment i get the first email twice!
//Loop trough ContactDetails and get the emails.
if (i == subContactIdlenght){
var subContactDetailslength = $scope.subContactDetails.length;
for(var p=0; p < subContactDetailslength; p++) {
console.log($scope.subContactDetails[p].mail);
var number = $scope.subContactDetails[p].mail;
$scope.subContactmail.push(number);
};
};
}).
error(function(data, status, headers, config) {
$scope.errormessage = data;
console.log(data);
});
};//ENDWHILE
console.log(data);
}).
error(function(data, status, headers, config) {
$scope.errormessage = data;
console.log(data);
});
答案 0 :(得分:2)
你有2个解决方案
使用promise API(推荐):
类似的东西
var wheatherPromise = $http.get(...);
var timePromise = $http.get(...);
var combinedPromise = $q.all({
wheather: wheatherPromise,
time: timePromise
})
combinedPromise.then(function(responses) {
console.log('the wheather is ', responses.wheather.data);
console.log('the time is ', responses.time.data);
});
OR
只需执行以下操作:
避免在for循环中定义$ http.get,导致意外行为
答案 1 :(得分:0)
我认为你需要的是promises/deferred API。