对于另一个我们试图淡化RGB色彩空间(从一种颜色到另一种颜色)的项目。 作为概念证明,我们在JavaScript中构建逻辑。作为最终结果,div的背景应该逐步改变为给定的颜色。 但在我们的例子中,div只是设置为最终颜色,并没有显示开始和结束颜色之间的步骤。
既然我们无法让它发挥作用,我们的问题:这里有什么问题?是逻辑缺陷还是我们的JS技能:)?
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>
</head>
<body>
<script>
$(function() {
var colors = [];
$('#go').click(function() {
console.log($('#red1').val()+" "+$('#green1').val()+" "+$('#blue1').val()+" "+$('#red2').val()+" "+$('#green2').val()+" "+$('#blue2').val());
slidecolor($('#red1').val(), $('#green1').val(), $('#blue1').val(), $('#red2').val(), $('#green2').val(), $('#blue2').val());
readArray();
});
function slidecolor(StartsR, StartsG, StartsB, aimR, aimG, aimB) {
StartsR = parseInt(StartsR);
StartsG = parseInt(StartsG);
StartsB = parseInt(StartsB);
aimR = parseInt(aimR);
aimG = parseInt(aimG);
aimB = parseInt(aimB);
if(aimR >= StartsR)
{
var directionR = 1;
console.log("größer");
var distanceR = aimR - StartsR;
}
else
{
var directionR = 0;
console.log("kleiner");
var distanceR = StartsR - aimR;
}
if(aimB >= StartsB)
{
var directionB = 1;
var distanceB = aimB - StartsB;
}
else
{
var directionB = 0;
var distanceB = StartsB - aimB;
}
if(aimG >= StartsG)
{
var directionG = 1;
var distanceG = aimG - StartsG;
}
else
{
var directionG = 0;
var distanceG = StartsG - aimG;
}
if((distanceR >= distanceB) && (distanceR >= distanceG)) { var distance = distanceR; }
if((distanceG >= distanceR) && (distanceG >= distanceB)) { var distance = distanceG; }
if((distanceB >= distanceR) && (distanceB >= distanceG)) { var distance = distanceB; }
var stepsR = Math.round(distance/distanceR);
var stepsG = Math.round(distance/distanceG);
var stepsB = Math.round(distance/distanceB);
console.log(distance+" "+distanceR);
console.log(stepsR+" "+stepsG+" "+stepsB);
var tmpstepsR = 0;
var tmpstepsG = 0;
var tmpstepsB = 0;
for(i=0; i<=distance; i++) {
console.log(i);
if(i==0)
{
console.log("FIRST RUN");
if(directionR == 1) {
var tmpR = StartsR + 1;
tmpstepsR = stepsR;
}
else
{
var tmpR = StartsR - 1;
tmpstepsR = stepsR + 1;
}
if(directionG == 1) {
var tmpG = StartsG + 1;
tmpstepsG = stepsG;
}
else
{
var tmpG = StartsG - 1;
tmpstepsG = stepsG;
}
if(directionB == 1) {
var tmpB = StartsB + 1;
tmpstepsB = stepsB;
}
else
{
tmpstepsB = stepsB;
var tmpB = StartsB - 1;
}
}
else
{
console.log("NEXT RUN");
if(((stepsR == i) || (tmpstepsR == i)) && tmpR != aimR)
{
tmpstepsR = tmpstepsR + stepsR;
if(directionR == 1) {
var tmpR = tmpR + stepsR;
}
else
{
var tmpR = tmpR - stepsR;
}
}
if(((stepsG == i) || (tmpstepsG == i)) && tmpG != aimG)
{
tmpstepsG = tmpstepsG + stepsG;
if(directionG == 1) {
var tmpG = tmpG + stepsG;
}
else
{
var tmpG = tmpG - stepsG;
}
}
if(((stepsB == i) || (tmpstepsB == i)) && tmpB != aimB)
{
tmpstepsB = tmpstepsB + stepsB;
if(directionB == 1) {
var tmpB = tmpB + stepsB;
}
else
{
var tmpB = tmpB - stepsB;
}
}
}
console.log('rgb('+ tmpR +','+ tmpG +','+ tmpB +')');
colors.push('rgb('+ tmpR +','+ tmpG +','+ tmpB +')');
}
}
function readArray(){
colors.forEach(function(entry){
timeOut(entry);
$('#color').css("background-color", entry);
});
}
function timeOut(entry){
setTimeout(function(){$('#color').css("background-color", entry);}, 3000);
}
});
</script>
<h1>Farbe 1</h1>
red: <input id="red1">
green: <input id="green1">
blue: <input id="blue1">
<h1>Farbe 2</h2>
red: <input id="red2">
green: <input id="green2">
blue: <input id="blue2">
<button id="go">LET'S GO</button>
<div id="color" style="width:500px;height:500px"></div>
</body>
</html>
请注意,某些部件可能有点马车或丑陋,因为它只是第一次尝试。最后一部分是我们添加了一些时间,是最后的手段,可能不是最佳实践......
编辑:jsfiddle
答案 0 :(得分:1)
在readArray
中,您将遍历colors
数组中的所有条目。这种迭代花费很少的时间(因为,比你注意到的更快)。在 迭代期间,所有 3秒超时都已设置。它们没有排序,它们都被设置为在forEach
完成后约3秒执行。
您需要正确排序回调:
function readArray(){
timeOut(colors, 0);
}
function timeOut(array, index){
var entry = colors[index];
$('#color').css("background-color", entry);
var nextIndex = index + 1;
if(nextIndex < array.length){
setTimeout(function(){
timeOut(array, nextIndex);
}, 30);
}
}
基本上,在执行当前“步骤”时,您可以设置下一步的超时。
<强> Example Fiddle 强>
请注意我将每步的超时时间设置为30
ms,因此您实际上可以注意到淡入淡出。
(而不是readArray();
,您当然可以使用timeOut(colors, 0);
,因此您可以完全删除readArray