Question

我有两个看起来像

的数组

var monthNames = [ "January", "January", "January", "April", "April", "December", "August", "August", "November", "November", "November", "December" ];

var monthRange = [ "January", "February", "March", "April", "May", "June",
"July", "August", "September", "October", "November", "December" ];

现在我想知道我应该如何在JS中工作，这样我就可以获得一个新的数组，其中包含12个元素（每月一个）并计算它。所以它会是这样的 -

[3, 0, 0, 2, 0, 0, 0, 2, 0, 0, 3, 1]

此处的计数是monthRange的顺序，它为monthNames中的每个月提供了计数。

所以这里

January : 3, 
April: 2, 
December: 1,
August: 2, 
November: 3, 
December : 1

Answer 1

这样就可以了：

var counts = monthRange.map(function(val) {
    var count = 0;
    for (var i = 0, j = monthNames.length; i < j; i++) {
        if (val === monthNames[i]) count++;
    }
    return count;
});

Answer 2

您可map超过monthRange，然后过滤monthNames以返回每月的出现次数：

monthRange.map(function(month) {
    return monthNames.filter(function(n) { return n === month }).length;
});

Answer 3

使用下划线你可以这样做：

_.reduce(array, function(memo, month) { 
    memo[month] = (memo[month] === undefined ? 0 : memo[month]) + 1; 
    return memo
}, {})

在您的情况下，它看起来像

   var countMonths = function(array, m) {
       return  _.reduce(array, function(memo, month) { 
           memo[month] = (memo[month] === undefined ? 0 : memo[month]) + 1; 
           return memo
       }, m)   
   } 

   var memo = countMonths(monthNames, {})
   memo = countMonths(monthRange, memo)

Answer 4

尝试Object跟踪频率：

var freq = function(list) {
  var o = {};
  var l = list.length;
  var v;
  while (v = list[--l])
    o[v] = o[v] !== undefined ? o[v] + 1 : 1;
  return o;
};

console.log(freq(["January", "January", "January", "April", "April", "December", "August", "August", "November", "November", "November", "December"]));

alert(JSON.stringify(freq(["apple", "mangoe", "apple"])));

Open console...

在Javascript中从另一个数组创建一组出现的数组

4 个答案: