Question

我一直想着如何在点击ListActivity中的一行时整天弹出一个webview。点击它时我甚至无法显示Toast。需要帮助

对于想要学习的网络开发人员Android，我还是新手。谢谢。

包com.mf.ar;

import org.json.JSONArray; import org.json.JSONException; import org.json.JSONObject;

import android.app.Activity; import android.app.AlertDialog; import android.app.ListActivity; import android.os.Bundle; import android.util.Log; import android.view.View; import android.view.Window; import android.webkit.WebChromeClient; import android.webkit.WebView; import android.webkit.WebViewClient; import android.widget.ArrayAdapter; import android.widget.Toast;

公共类ListViewer扩展了ListActivity { private String mJSON; private String [] listRows; private String [] listRowsURI;

 /** Called when the activity is first created. */
 @Override
 public void onCreate(Bundle savedInstanceState) {
     super.onCreate(savedInstanceState);
     //setContentView(R.layout.listview);

     Bundle the = getIntent().getExtras();
     this.mJSON = the.getString("JSON");
     Log.i("ListViewIntentJSON", this.mJSON);

     try {
JSONObject UrbJSON = new JSONObject(mJSON);

JSONObject UrbQuery = UrbJSON.getJSONObject("query");
int rows = UrbQuery.getInt("row");
Log.i("UrbRows", String.format("%d",rows));

JSONArray resultArray = UrbJSON.getJSONArray("result");

this.listRows = new String[rows];
for(int i=0; i<rows; i++) { 
 this.listRows[i] = resultArray.getJSONObject(i).
   getString("business_name").toString();
}
this.listRowsURI = new String[rows];
for(int i=0; i<rows; i++) { 
 this.listRowsURI[i] = resultArray.getJSONObject(i).
   getString("business_uri_mobile").toString();
}
     } catch(JSONException e) {
      e.printStackTrace();
     }

     this.setListAdapter(new ArrayAdapter<String>(this, 
             android.R.layout.simple_list_item_1, ListViewer.this.listRows));
 }

 @Override
 protected void onListItemClick(android.widget.ListView l, View v, int position, long id) {
  super.onListItemClick(l, v, position, id);

  String theURI = ListViewer.this.listRowsURI[position].toString();
  /*String theURI = ListViewer.this.listRowsURI[position].toString();
  //String theURI = "http://www.mediafusion.web.id";

  WebView webview = new WebView(this);
  //setContentView(webview);
  //addContentView(webview, null);
  webview.getSettings().setJavaScriptEnabled(true);
  getWindow().requestFeature(Window.FEATURE_PROGRESS);
  final Activity activity = this;
webview.setWebChromeClient(new WebChromeClient() {
  public void onProgressChanged(WebView view, int progress) {
    // Activities and WebViews measure progress with different scales.
    // The progress meter will automatically disappear when we reach 100%
    activity.setProgress(progress * 1000);
  }
});
webview.setWebViewClient(new WebViewClient() {
  public void onReceivedError(WebView view, int errorCode, String description, String failingUrl) {
    Toast.makeText(activity, "Oh no! " + description, Toast.LENGTH_SHORT).show();
  }
});
  webview.loadUrl(theURI);*/

  Toast.makeText(ListViewer.this.getApplicationContext(), theURI, Toast.LENGTH_SHORT);

 }

}

Answer 1

删除代码中出现的所有getApplicationContext()，事情会对您有所帮助。 ListViewer是Context - 只需在Toast中使用它。

关于WebView，我认为您可以更好地制作自己的活动并从{{1}}启动该活动。

WebList的Android ListActivity OnListItemClick错误

1 个答案: