我有一个bash脚本来构建一个rub .deb包,我想在其中使用服务器架构......
我安装了ansible并运行了ansible localhost -m setup,它给了我ansible事实......
> ansible localhost -m setup
localhost | success >> {
"ansible_facts": {
"ansible_all_ipv4_addresses": [
"10.10.5.200"
],
"ansible_all_ipv6_addresses": [
"fe80::4c2:ccff:fe82:8d8c"
],
"ansible_architecture": "x86_64",
"ansible_bios_date": "06/02/2014",
...
我想使用检测到的架构" ansible_architecture":" x86_64"在我的fpm命令中的shell脚本中:
currently :
fpm -s dir -t deb -n ruby$version -v $rubyversion -C $destdir \
-p ruby-VERSION_ARCH~trusty.deb -d "libstdc++6 (>= 4.4.3)" \
-d "libc6 (>= 2.6)" -d "libffi6 (>= 3.0.10)" -d "libgdbm3 (>= 1.8.3)" \
-d "libncurses5 (>= 5.7)" -d "libreadline6 (>= 6.1)" \
-d "libssl1.0.0 (>= 1.0.1)" -d "zlib1g (>= 1:1.2.2)" \
-d "libyaml-0-2 (>= 0.1.4-2)" \
usr/local/bin usr/local/lib usr/local/share/man usr/local/include
# VERSION_ARCH is giving me 'amd64' and I would like to use
# ansible_architecture ( which is detecting "x86_64"....
我可能不必使用安全事实来检测它......
#我试着在我的脚本开头写
$架构= uname -m
#但它确实给了我" x86_64"作为变量...
感谢您的建议
答案 0 :(得分:1)
得到了它: 插入
architecture="$(uname -m)"
echo "architecture: $architecture"
在我的脚本开头并使用$ architecture作为参数