我在表rel_user_article
中有下一个数据集+---------+------------+
| user_id | article_id |
+---------+------------+
| 1 | -1 |
| 97 | 153 |
+---------+------------+
此表格暗示了下一个逻辑:每位作者必须至少有一篇文章,每篇文章必须至少有一位作者。当作者没有文章时,表格必须有假关系:( uid,-1)
当作者添加他的第一篇文章时,必须删除这种假关系。
我有创建新关系和删除假关系的存储过程。 删除假关系看起来像这样:
CREATE PROCEDURE `rel_delete_fake`(IN `ids` TEXT, IN `tbl` VARCHAR(255),
IN `fake_f` VARCHAR(255), IN `real_f` VARCHAR(255))
MODIFIES SQL DATA
proc: begin
if (`ids` = '') then
leave proc;
end if;
set @s = concat('DELETE FROM ', `tbl`, ' WHERE (', `fake_f`,
' = "-1" AND ', `real_f`, ' IN (', `ids`, '))');
prepare qr from @s;
execute qr;
deallocate prepare qr;
end proc
创造"真实"关系看起来像这样:
CREATE DEFINER=`root`@`localhost` PROCEDURE `rel_create`(IN `ids1` TEXT,
IN `ids2` TEXT, IN `tbl` VARCHAR(255), IN `field1` VARCHAR(255),
IN `field2` VARCHAR(255))
MODIFIES SQL DATA
proc: begin
set @cur = 0;
set @id1_cur = 0;
set @id2_cur = 0;
set @id1_cur_old = NULL;
set @id2_cur_old = NULL;
if (`ids1` = '' or `ids2` = '') then
leave proc;
end if;
set @sql_str = concat('insert into ', `tbl`, ' (', `field1`, ', ', `field2`, ") values (?, ?)");
prepare qr from @sql_str;
loop1: loop
set @cur = @cur + 1;
set @id1_cur = substring_index(substring_index(`ids1`, ',', @cur), ',', -1);
set @id2_cur = substring_index(substring_index(`ids2`, ',', @cur), ',', -1);
if (@id1_cur = @id1_cur_old and @id2_cur = @id2_cur_old) then
leave proc;
end if;
execute qr using @id1_cur, @id2_cur;
set @id1_cur_old = @id1_cur;
set @id2_cur_old = @id2_cur;
end loop loop1;
deallocate prepare qr;
-- deleting fake records that became needless
-- even this doesn't work
call `rel_delete_fake`('1','rel_user_article','article_id','user_id');
leave proc;
-- deleting fake records that became needless
call `rel_delete_fake`(`ids1`, `tbl`, `field2`, `field1`);
call `rel_delete_fake`(`ids2`, `tbl`, `field1`, `field2`);
end proc
删除假关系的程序有效。创建关系的过程只会创建新记录,但甚至不会调用rel_delete_fake过程。
对于测试我发出下一个电话:
call `rel_create`('1','153','rel_user_article','user_id','article_id');
并得到结果:
+---------+------------+
| user_id | article_id |
+---------+------------+
| 1 | -1 |
| 1 | 153 |
| 97 | 153 |
+---------+------------+
为什么不删除此(1,-1)?
答案 0 :(得分:0)
我发现了错误。必须有"离开loop1;"代替"离开;"在循环中。