Question

我从here得到了我的更改问题。我有以下代码：

from nltk.corpus import stopwords
>>> def content_text(text):
    stopwords = nltk.corpus.stopwords.words('english')
    content = [w for w in text if w.lower() in stopwords]
    return content

我如何打印文本中10个最常出现的单词1）包括和2）不包括停用词？

Answer 1

nltk中有一个FreqDist函数

import nltk
allWords = nltk.tokenize.word_tokenize(text)
allWordDist = nltk.FreqDist(w.lower() for w in allWords)

stopwords = nltk.corpus.stopwords.words('english')
allWordExceptStopDist = nltk.FreqDist(w.lower() for w in allWords if w not in stopwords)

提取10个最常见的：

mostCommon= allWordDist.most_common(10).keys()

Answer 2

在函数的is stopwords上不确定，我认为它必须是in，但您可以使用most_common(10)的反驳来获得最常见的10个：

from collections import Counter
from string import punctuation


def content_text(text):
    stopwords = set(nltk.corpus.stopwords.words('english')) # 0(1) lookups
    with_stp = Counter()
    without_stp  = Counter()
    with open(text) as f:
        for line in f:
            spl = line.split()
            # update count off all words in the line that are in stopwrods
            with_stp.update(w.lower().rstrip(punctuation) for w in spl if w.lower() in stopwords)
               # update count off all words in the line that are not in stopwords
            without_stp.update(w.lower().rstrip(punctuation)  for w in spl if w  not in stopwords)
    # return a list with top ten most common words from each 
    return [x for x in with_stp.most_common(10)],[y for y in without_stp.most_common(10)]
wth_stop, wthout_stop = content_text(...)

如果你传入一个nltk文件对象只是迭代它：

def content_text(text):
    stopwords = set(nltk.corpus.stopwords.words('english'))
    with_stp = Counter()
    without_stp  = Counter()
    for word in text:
        # update count off all words in the line that are in stopwords
        word = word.lower()
        if word in stopwords:
             with_stp.update([word])
        else:
           # update count off all words in the line that are not in stopwords
            without_stp.update([word])
    # return a list with top ten most common words from each
    return [k for k,_ in with_stp.most_common(10)],[y for y,_ in without_stp.most_common(10)]

print(content_text(nltk.corpus.inaugural.words('2009-Obama.txt')))

nltk方法包括标点符号，因此可能不是您想要的。

Answer 3

你可以试试这个：

for word, frequency in allWordsDist.most_common(10):
    print('%s;%d' % (word, frequency)).encode('utf-8')

打印包含和排除停用词的10个最常出现的文字

3 个答案: