Question

我在mysql查询失败时包含一个php文件。包含文件不起作用。以下是不起作用的片段。请检查。

$countsql2='SELECT * from table_name';

$countsql3 = mysqli_query($mysqli, $countsql2) or die("
  <div id='fail_container'>
    <div id='fail_grid'>
      <span class='searched_invalid'>There seems to be an issue with the server connectivity.Please Try again later.</span><br />
      <span class='searched_invalid'>We have an option to check out the categories here</span>  
    </div>
  </div>"
include 'file1.php');

我想在查询失败时显示包含的php文件。但是当我在模具零件中移除包含零件时，它运行正常。但我想用include php文件运行它。

请帮我纠正这个问题，或者是否可以通过其他方式完成。

Answer 1

多数民众赞成因为die停止了您的申请。

你能做的是：

if ( !$countsql3 = mysqli_query( $mysqli, $countsql2 ) )
{
    echo "<div id='fail_container'>
        <div id='fail_grid'>
            <span class='searched_invalid'>There seems to be an issue with the server connectivity.Please Try again later.</span><br />
            <span class='searched_invalid'>We have an option to check out the categories here</span>    
        </div>
    </div>";

    include('file1.php');

    die;
}

Answer 2

您应该在if语句中执行此操作，如下所示：

$countsql2='SELECT * from table_name';

$countsql3 = mysqli_query($mysqli, $countsql2);

if (!$countsql3) {
    echo "<div id='fail_container'>
        <div id='fail_grid'>
        <span class='searched_invalid'>There seems to be an issue with the server connectivity.Please Try again later.</span><br />
        <span class='searched_invalid'>We have an option to check out the categories here</span>    
        </div>
    </div>"

    include 'file1.php';
    exit;
}

Answer 3

你应该试试......

的完整路径

file1.php

如果file1.php仍然无法显示，您可以尝试使用$_SERVER["DOCUMENT_ROOT"];获取根文件夹并添加当前位置。

error_reporting(E_ALL); 
ini_set('display_errors', 1);
$countsql2='SELECT * from table_name';
if ( !$countsql3 = mysqli_query( $mysqli, $countsql2 ) )
{
    echo "<div id='fail_container'>
        <div id='fail_grid'>
            <span class='searched_invalid'>There seems to be an issue with the server connectivity.Please Try again later.</span><br />
            <span class='searched_invalid'>We have an option to check out the categories here</span>    
        </div>
    </div>";

    require('/full/path/to/file/file1.php');
}

文件包括在php中查询失败的情况下不工作

3 个答案: