我正在制作一个石头剪刀游戏。一切正常,除了我无法理解为什么第二个while循环不能在这段代码中工作。我想制作程序,以便用户不输入" R"或" P"或" S"然后用户将被告知这是一个无效的条目,它将提示用户再次输入他们的答案。它对于player1完全正常,但它不适用于player2。对于player2,如果你没有输入" R"或者" P或" S",然后它会提示您再次输入一个新值,但只会输入一次,无论您输入什么。所有帮助都赞赏!
if playGame == "Y":
print("Ok, here we go.")
player1 = input("Player1, what is your choice, R, P, or S? ")
player1 = player1.upper()
while player1 != 'R' and player1 != 'P' and player1 != 'S':
player1 = input("Invalid answer. Please answer R, P, or S: ")
player1 = player1.upper()
player2 = input("Player2, what is your choice, R, P, or S? ")
player2 = player2.upper()
while player2 != 'R' and player2 != 'P' and player2 != 'S':
player2 = input("Invalid answer. Please answer R, P, or S: ")
player2 = player1.upper()
答案 0 :(得分:5)
错误在最后一行
player2 = player1.upper()
应该是
player2 = player2.upper()
答案 1 :(得分:0)
当用户输入无效值时,使用while
循环一次又一次地询问用户。
代码:
playGame = raw_input("You want to play game: if yes then enter Y:").upper()
if playGame == "Y":
print("Ok, here we go.")
player1 = ''
while 1:
player1 = raw_input("Player1, what is your choice, R, P, or S?:").upper()
if player1 not in ['R', 'P', 'S']:
print "Invalid answer."
else:
break
player2 = ''
while 1:
player2 = raw_input("Player2, what is your choice, R, P, or S?:").upper()
if player2 not in ['R', 'P', 'S']:
print "Invalid answer."
else:
break
print "player1:", player1
print "player2:", player2
输出:
vivek@vivek:~/Desktop/stackoverflow$ python 7.py
You want to paly game: if yes then enter Y:Y
Ok, here we go.
Player1, what is your choice, R, P, or S?:a
Invalid answer.
Player1, what is your choice, R, P, or S?:R
Player2, what is your choice, R, P, or S?:w
Invalid answer.
Player2, what is your choice, R, P, or S?:q
Invalid answer.
Player2, what is your choice, R, P, or S?:s
player1: R
player2: S