Question

我试图在动作属性上设置一个块，但那不起作用......任何想法？我知道UIView动画...方法有一个完成块，但不确定UIDynamicAnimations。

编辑：添加代码

[self.animator removeAllBehaviors];
UIGravityBehavior *gravityBehaviour = [[UIGravityBehavior alloc] initWithItems:@[self.onscreen]];
gravityBehaviour.gravityDirection = CGVectorMake(0, 10);
gravityBehaviour.action = ^{
    if(self.onscreen.frame.origin.y > [UIScreen mainScreen].bounds.size.height)
       [self.onscreen removeFromSuperview];
    NSLog(@"locations is %f, height is %f", self.onscreen.frame.origin.y, [UIScreen mainScreen].bounds.size.height);
};
[self.animator addBehavior:gravityBehaviour];

UIDynamicItemBehavior *itemBehaviour = [[UIDynamicItemBehavior alloc] initWithItems:@[self.onscreen]];
[itemBehaviour addAngularVelocity:-M_PI_2 forItem:self.onscreen];

[self.animator addBehavior:itemBehaviour];

输出反映出，即使在屏幕外，视图也会继续移动。

Answer 1

所以我通过在if语句中再抛出一个东西来解决它：[animator removeAllBehaviors];这似乎可以解决问题。

Answer 2

  #id span:hover{
   color: red;
  }

如何在UIGravityBehavior将其移出屏幕后删除UIView？

2 个答案: