如何使用带有PHP的Gmail API获取所有收件箱邮件?我可以获得消息ID,除此之外什么都没有。我需要获取主题,发件人和消息文本。
$list = $gmail->users_messages->listUsersMessages('me',['maxResults' => 10000, 'q' => 'category:primary']);
$messageList = $list->getMessages();
$client->setUseBatch(true);
$batch = new Google_Http_Batch($client);
foreach($messageList as $mlist){
$batch->add($gmail->users_messages->get('me',$mlist->id, ['format' => 'raw']),$mlist->id);
}
$batchMessages = $batch->execute();
$inboxMessage = [];
foreach($batchMessages as $dMessage){
$messageId = $dMessage->id;
$messageSnippet = $dMessage->snippet;
$dcMessage = base64url_decode($dMessage->getRaw());
$params['include_bodies'] = true;
$params['decode_bodies'] = true;
$params['decode_headers'] = true;
$mimeDecode = new Mail_mimeDecode($dcMessage);
$mimeSubject = $mimeDecode->decode($params)->headers['subject'];
$inboxMessage[] = [
'messageId' => $messageId,
'messageSubject' => $messageSubject
];
}
答案 0 :(得分:8)
这就是我做到的。
$list = $gmail->users_messages->listUsersMessages('me',['maxResults' => 10, 'q' => $search]);
$messageList = $list->getMessages();
$inboxMessage = [];
foreach($messageList as $mlist){
$optParamsGet2['format'] = 'full';
$single_message = $gmail->users_messages->get('me',$mlist->id, $optParamsGet2);
$message_id = $mlist->id;
$headers = $single_message->getPayload()->getHeaders();
$snippet = $single_message->getSnippet();
foreach($headers as $single) {
if ($single->getName() == 'Subject') {
$message_subject = $single->getValue();
}
else if ($single->getName() == 'Date') {
$message_date = $single->getValue();
$message_date = date('M jS Y h:i A', strtotime($message_date));
}
else if ($single->getName() == 'From') {
$message_sender = $single->getValue();
$message_sender = str_replace('"', '', $message_sender);
}
}
$inboxMessage[] = [
'messageId' => $message_id,
'messageSnippet' => $snippet,
'messageSubject' => $message_subject,
'messageDate' => $message_date,
'messageSender' => $message_sender
];
}