您好我正在尝试使用表单软删除和还原用户,我使用了几个用于身份验证的用户身份以及Zizaco Confide和Zizaco Entrust的角色。我已将以下内容添加到user.php模型
中use SoftDeletingTrait;
use ConfideUser;
use HasRole;
protected $softDelete = true;
我正在进行测试,以便对此进行测试:
Route::get('/deleteme', function(){
User::find(2)->delete();
return 'done';
});
并且这更新了时间戳字段,但是我想把它放到我的控制器中来整理并给它一个表单。所以我在用户表中做到了这一点:
@if(empty($user->deleted_at))
{{Form::open(['method'=>'PATCH','action'=>
['UsersController@softDeleteUser',$user->id]])}}
<button type="submit">Suspend</button>
{{Form::close()}}
@else
{{Form::open(['method'=>'delete','action'=>
['UsersController@restoreUser',$user->id]])}}
<button type="submit">Re-activate</button>
{{Form::close()}}
@endif
并在我的控制器中:
public function softDeleteUser($id){
$user = User::find($id);
$user->delete();
// redirect
return Redirect::to('/admin');
}
public function restoreUser($id) {
User::find($id)->restore();
$user->save();
Redirect::to("/admin");
}
在我的路线中:
Route::post('/admin/user/{resource}/delete',
array('as' => 'admin.user.delete', 'uses'
=>'UsersController@softDeleteUser'));
Route::post('/admin/user/{resource}/restore',
array('as' => 'admin.user.restore',
'uses' =>'UsersController@restoreUser'));
但是我收到了这个错误:
Symfony \ Component \ HttpKernel \ Exception \ MethodNotAllowedHttpException
任何想法我做错了什么?
答案 0 :(得分:1)
您已将两个表单设置为使用PATCH和DELETE方法,但您的路由设置为POST(Route::post
)。
您可以更改路线:
Route::patch('/admin/user/{resource}/delete',
array('as' => 'admin.user.delete', 'uses'
=>'UsersController@softDeleteUser'));
Route::delete('/admin/user/{resource}/restore',
array('as' => 'admin.user.restore',
'uses' =>'UsersController@restoreUser'));
或删除表单中的method
(默认为POST)
{{Form::open(['action'=> ['UsersController@softDeleteUser',$user->id]])}}
<button type="submit">Suspend</button>
{{Form::close()}}
和
{{Form::open(['action'=> ['UsersController@restoreUser',$user->id]])}}
<button type="submit">Re-activate</button>
{{Form::close()}}