我有一个Python初学者编码类。我们正在使用的书是#34; Coding for Penetration Testers Building Better Tools"。在第二章中,我们开始创建Python脚本,我似乎无法弄清楚这个脚本有什么问题我应该从书中重新输入。见下文。
import httplib, sys
if len(sys.argv) < 3:
sys.exit("Usage " + sys.argv[0] + " <hostname> <port>\n")
host = sys.argv[1]
port = sys.argv[2]
client = httplib.HTTPConnection(host,port)
client.request("GET","/")
resp = client.getresponse()
client.close()
if resp.status == 200:
print host + " : OK"
sys.exit()
print host + " : DOWN! (" + resp.status + " , " + resp.reason + ")"
运行代码后,我在第20行(最后一条打印行)上收到错误,说明:
selmer@ubuntu:~$ python /home/selmer/Desktop/scripts/arguments.py google.com 80
Traceback (most recent call last):
File "/home/selmer/Desktop/scripts/arguments.py", line 20, in <module>
print host + " : DOWN! (" + resp.status + " , " + resp.reason + ")"
TypeError: cannot concatenate 'str' and 'int' objects
所有代码都在Ubuntu 14.04中在带有Konsole的VM中运行,并在Gedit中创建。任何帮助将不胜感激!
答案 0 :(得分:0)
从以下位置替换打印行:
print host + " : DOWN! (" + resp.status + " , " + resp.reason + ")"
使用:
print '%s DOWN! (%d, %s)' % (host, resp.status, resp.reason)
原始行尝试将一个int(resp.status
)附加到字符串,如错误消息所示。