如何将union结构转换为Delphi记录?
这是C ++结构
union {
struct {
uint32_t l_i_reserved1;
} linux1;
struct {
uint32_t h_i_translator;
} hurd1;
struct {
uint32_t m_i_reserved1;
} masix1;
} osd1; /* OS dependent 1 */
这是我的尝试,但我不认为这是对的?
osd1 : Record
case Cardinal of
0: (l_i_reserved1 : Cardinal);
1: (h_i_translator : Cardinal);
2: (m_i_reserved1 : Cardinal);
end;
我还需要将此结构转换为Record
union {
struct {
uint8_t l_i_frag; /* Fragment number */
uint8_t l_i_fsize; /* Fragment size */
uint16_t i_pad1;
uint16_t l_i_uid_high; /* these 2 fields */
uint16_t l_i_gid_high; /* were reserved2[0] */
uint32_t l_i_reserved2;
} linux2;
struct {
uint8_t h_i_frag; /* Fragment number */
uint8_t h_i_fsize; /* Fragment size */
uint16_t h_i_mode_high;
uint16_t h_i_uid_high;
uint16_t h_i_gid_high;
uint16_t h_i_author;
} hurd2;
struct {
uint8_t m_i_frag; /* Fragment number */
uint8_t m_i_fsize; /* Fragment size */
uint16_t m_pad1;
uint32_t m_i_reserved2[2];
} masix2;
} osd2; /* OS dependent 2 */
相同的概念是否适用?
由于