我陷入了一种不可能的境地。我有来自外太空的JSON（他们无法改变它）。这是JSON
{
user:'180111',
title:'I\'m sure "E pluribus unum" means \'Out of Many, One.\' \n\nhttp://en.wikipedia.org/wiki/E_pluribus_unum.\n\n\'',
date:'2007/01/10 19:48:38',
"id":"3322121",
"previd":112211,
"body":"\'You\' can \"read\" more here [url=http:\/\/en.wikipedia.org\/?search=E_pluribus_unum]E pluribus unum[\/url]'s. Cheers \\*/ :\/",
"from":"112221",
"username":"mikethunder",
"creationdate":"2007\/01\/10 14:04:49"
}
“它远不是一个有效的JSON”，我说。他们的反应是“嗯！但是Javascript可以在没有抱怨的情况下阅读它”：
<html>
<script type="text/javascript">
var obj = {"PUT JSON FROM UP THERE HERE"};
document.write(obj.title);
document.write("<br />");
document.write(obj.creationdate + " " + obj.date);
document.write("<br />");
document.write(obj.body);
document.write("<br />");
</script>
<body>
</body>
</html>
问题
我应该通过.NET（4）读取并解析这个字符串，它打破了Json.org的C＃部分中提到的14个库中的3个（没有尝试其余部分）。为了解决问题，我编写了以下函数来解决单引号和双引号的问题。
public static string JSONBeautify(string InStr){
bool inSingleQuote = false;
bool inDoubleQuote = false;
bool escaped = false;
StringBuilder sb = new StringBuilder(InStr);
sb = sb.Replace("`", "<°)))><"); // replace all instances of "grave accent" to "fish" so we can use that mark later.
// Hopefully there is no "fish" in our JSON
for (int i = 0; i < sb.Length; i++) {
switch (sb[i]) {
case '\\':
if (!escaped)
escaped = true;
else
escaped = false;
break;
case '\'':
if (!inSingleQuote && !inDoubleQuote) {
sb[i] = '"'; // Change opening single quote string markers to double qoute
inSingleQuote = true;
} else if (inSingleQuote && !escaped) {
sb[i] = '"'; // Change closing single quote string markers to double qoute
inSingleQuote = false;
} else if (escaped) {
escaped = false;
}
break;
case '"':
if (!inSingleQuote && !inDoubleQuote) {
inDoubleQuote = true; // This is a opening double quote string marker
} else if (inSingleQuote && !escaped) {
sb[i] = '`'; // Change unescaped double qoute to grave accent
} else if (inDoubleQuote && !escaped) {
inDoubleQuote = false; // This is a closing double quote string marker
} else if (escaped) {
escaped = false;
}
break;
default:
escaped = false;
break;
}
}
return sb.ToString()
.Replace("\\/", "/") // Remove all instances of escaped / (\/) .hopefully no smileys in string
.Replace("`", "\\\"") // Change all "grave accent"s to escaped double quote \"
.Replace("<°)))><", "`") // change all fishes back to "grave accent"
.Replace("\\'","'"); // change all escaped single quotes to just single quote
}
现在JSONlint只抱怨属性名称，我可以使用JSON.NET和SimpleJSON库来解析JSON之上。
问题
我确信我的代码不是修复提到的JSON的最佳方法。 有没有我的代码可能会破坏的情况？有没有更好的方法呢？
答案 0 :(得分：8)
您需要通过JavaScript运行它。在 .net 中启动JavaScript解析器。将字符串作为JavaScript的输入，并使用JavaScript的本机JSON.stringify进行转换：
obj = {
"user":'180111',
"title":'I\'m sure "E pluribus unum" means \'Out of Many, One.\' \n\nhttp://en.wikipedia.org/wiki/E_pluribus_unum.\n\n',
"date":'2007/01/10 19:48:38',
"id":"3322121",
"previd":"112211",
"body":"\'You\' can \"read\" more here [url=http:\/\/en.wikipedia.org\/?search=E_pluribus_unum]E pluribus unum[\/url]'s. Cheers \\*/ :\/",
"from":"112221",
"username":"mikethunder",
"creationdate":"2007\/01\/10 14:04:49"
}
console.log(JSON.stringify(obj));
document.write(JSON.stringify(obj));
请记住，您获得的字符串（或更确切的对象）不是有效的JSON，无法使用JSON库进行解析。它需要首先转换为有效的JSON。但它是有效的JavaScript。
要完成此答案：您可以在 .Net 中使用JavaScriptSerializer。对于此解决方案，您将需要以下程序集：
System.Web.Script.Serialization
var webClient = new WebClient();
string readHtml = webClient.DownloadString("uri to your source (extraterrestrial)");
var a = new JavaScriptSerializer();
Dictionary<string, object> results = a.Deserialize<Dictionary<string, object>>(readHtml);
答案 1 :(得分：2)
这个怎么样：
string AlienJSON = "your alien JSON";
JavaScriptSerializer js = new JavaScriptSerializer();
string ProperJSON = js.Serialize(js.DeserializeObject(AlienJSON));
或者只是在反序列化后使用该对象而不是将其转换回字符串并将其传递给JSON解析器以获得额外的麻烦
正如Mouser还提到的那样，您需要在项目中包含System.Web.Script.Serialization来使用system.web.extensions.dll，并且需要将项目属性中的Target框架更改为.NET Framework 4。< / p>
修改
使用dynamic
JavaScriptSerializer js = new JavaScriptSerializer();
dynamic obj = js.DeserializeObject(AlienJSON);
string body = obj["body"];
或者你的JSON是一个数组
if (obj is Array) {
foreach(dynamic o in obj){
string body = obj[0]["body"];
// ... do something with it
}
}
答案 2 :(得分：-1)
这是我制作的可修复损坏的json的函数：
function fixJSON(json){
function bulkRegex(str, callback){
if(callback && typeof callback === 'function'){
return callback(str);
}else if(callback && Array.isArray(callback)){
for(let i = 0; i < callback.length; i++){
if(callback[i] && typeof callback[i] === 'function'){
str = callback[i](str);
}else{break;}
}
return str;
}
return str;
}
if(json && json !== ''){
if(typeof json !== 'string'){
try{
json = JSON.stringify(json);
}catch(e){return false;}
}
if(typeof json === 'string'){
json = bulkRegex(json, false, [
str => str.replace(/[\n\t]/gm, ''),
str => str.replace(/,\}/gm, '}'),
str => str.replace(/,\]/gm, ']'),
str => {
str = str.split(/(?=[,\}\]])/g);
str = str.map(s => {
if(s.includes(':') && s){
let strP = s.split(/:(.+)/, 2);
strP[0] = strP[0].trim();
if(strP[0]){
let firstP = strP[0].split(/([,\{\[])/g);
firstP[firstP.length-1] = bulkRegex(firstP[firstP.length-1], false, p => p.replace(/[^A-Za-z0-9\-_]/, ''));
strP[0] = firstP.join('');
}
let part = strP[1].trim();
if((part.startsWith('"') && part.endsWith('"')) || (part.startsWith('\'') && part.endsWith('\'')) || (part.startsWith('`') && part.endsWith('`'))){
part = part.substr(1, part.length - 2);
}
part = bulkRegex(part, false, [
p => p.replace(/(["])/gm, '\\$1'),
p => p.replace(/\\'/gm, '\''),
p => p.replace(/\\`/gm, '`'),
]);
strP[1] = ('"'+part+'"').trim();
s = strP.join(':');
}
return s;
});
return str.join('');
},
str => str.replace(/(['"])?([a-zA-Z0-9\-_]+)(['"])?:/g, '"$2":'),
str => {
str = str.split(/(?=[,\}\]])/g);
str = str.map(s => {
if(s.includes(':') && s){
let strP = s.split(/:(.+)/, 2);
strP[0] = strP[0].trim();
if(strP[1].includes('"') && strP[1].includes(':')){
let part = strP[1].trim();
if(part.startsWith('"') && part.endsWith('"')){
part = part.substr(1, part.length - 2);
part = bulkRegex(part, false, p => p.replace(/(?<!\\)"/gm, ''));
}
strP[1] = ('"'+part+'"').trim();
}
s = strP.join(':');
}
return s;
});
return str.join('');
},
]);
try{
json = JSON.parse(json);
}catch(e){return false;}
}
return json;
}
return false;
}