Question

抱歉我的英语。我想读一个大文件，但是当我读到错误时出现 outOfMemoryError 。我不明白如何在应用程序中使用内存。以下代码不起作用：

try {

    StringBuilder fileData = new StringBuilder(1000);
    BufferedReader reader = new BufferedReader(new FileReader(file));

    char[] buf = new char[8192];
    int bytesread = 0, 
        bytesBuffered = 0;

    while( (bytesread = reader.read( buf )) > -1 ) {

        String readData = String.valueOf(buf, 0, bytesread);
        bytesBuffered += bytesread;

        fileData.append(readData); //this is error

        if (bytesBuffered > 1024 * 1024) { 
            bytesBuffered = 0;
        }
    }

    System.out.println(fileData.toString().toCharArray());
} finally {

}

Answer 1

试试这个。这可能会有所帮助： -

try{
    BufferedReader reader = new BufferedReader(new FileReader(file));
    String txt = "";
    while( (txt = reader.read()) != null){
        System.out.println(txt);
    }
}catch(Exception e){
   System.out.println("Error : "+e.getMessage());
}

Answer 2

您需要预先分配一个大缓冲区以避免重新分配。

File file = ...;
StringBuilder fileData = new StringBuilder(file.size());

以大堆大小运行：

java -Xmx2G

====更新

使用缓冲区的while循环不需要太多内存来运行。像流一样处理输入，将搜索字符串与流匹配。这是一个非常简单的状态机。如果您需要搜索多个单词，可以找到TrieTree实现（支持流）。

// the match state model
...xxxxxxabxxxxxaxxxxxabcdexxxx...
         ab     a     abcd

    File file = new File("path_to_your_file");
    String yourSearchWord = "abcd";
    int matchIndex = 0;
    boolean matchPrefix = false;
    try (BufferedReader reader = new BufferedReader(new FileReader(file))) {
        int chr;
        while ((chr = reader.read()) != -1) {
            if (matchPrefix == false) {
                char searchChar = yourSearchWord.charAt(0);
                if (chr == searchChar) {
                    matchPrefix = true;
                    matchIndex = 0;
                }
            } else {
                char searchChar = yourSearchWord.charAt(++matchIndex);
                if (chr == searchChar) {
                    if (matchIndex == yourSearchWord.length() - 1) {
                        // match!!
                        System.out.println("match: " + matchIndex);
                        matchPrefix = false;
                        matchIndex = 0;
                    }
                } else {
                    matchPrefix = false;
                    matchIndex = 0;
                }
            }
        }
    }

Answer 3

你不应该在内存中保存这么大的文件，因为你已经没有了，正如你所看到的那样。由于您使用的是Java 7，因此需要手动将文件作为流读取并动态检查内容。否则，您可以使用Java 8的流API。这只是一个示例。它的工作原理，但请记住，由于编码问题，找到的单词的位置可能会有所不同，因此这不是生产代码：

import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;

public class FileReader
{
    private static String wordToFind = "SEARCHED_WORD";
    private static File file = new File("YOUR_FILE");
    private static int currentMatchingPosition;
    private static int foundAtPosition = -1;
    private static int charsRead;

    public static void main(String[] args) throws IOException
    {
        try (FileInputStream fis = new FileInputStream(file))
        {
            System.out.println("Total size to read (in bytes) : " + fis.available());

            int c;
            while ((c = fis.read()) != -1)
            {
                charsRead++;
                checkContent(c);
            }

            if (foundAtPosition > -1)
            {
                System.out.println("Found word at position: " + (foundAtPosition - wordToFind.length()));
            }
            else
            {
                System.out.println("Didnt't find the word!");
            }

        }
        catch (IOException e)
        {
            e.printStackTrace();
        }
    }

    private static void checkContent(int c)
    {
        if (currentMatchingPosition >= wordToFind.length())
        {
            //already found....
            return;
        }

        if (wordToFind.charAt(currentMatchingPosition) == (char)c)
        {
            foundAtPosition = charsRead;
            currentMatchingPosition++;
        }
        else
        {
            currentMatchingPosition = 0;
            foundAtPosition = -1;
        }
    }
}

读取大文件错误“outofmemoryerror”（java）

3 个答案: