我正在尝试检索所有任务的列表,其中每个任务都有开发人员和审阅者。我能够检索列表,但它包含developer_id和reviewer_id。如何检索包含开发人员名称和检索者名称的列表?
class Person < ActiveRecord::Base
end
class Unread_Object < ActiveRecord::Base
belongs_to :person
end
class Developer < Person
has_many :tasks
end
class Reviewer < Person
has_many :tasks
has_many :unread_objects
end
class Task < ActiveRecord::Base
belongs_to :developer
belongs_to :reviewer
has_many :documents
after_save :add_task_to_unread_objects
protected
def add_task_to_unread_objects
Person.find_each do |person|
Unread_Object.create(
:person_id => person.id,
:internal_object_id => self.internal_object_id,
:unread_cause => 'Create')
end
end
end
我尝试过的事情。
get '/taskslist' do
#Task.includes([:developer, :reviewer]).all.to_json
#Task.joins(:developer,:reviewer).select("tasks.*, people.*").to_json #works somewhat but only shows one name
#Task.includes(:reviewer.name,:developer.name).all.to_json #"undefined method `name' for :reviewer:Symbol"
#Task.find(:all, :include => {:people => :name}).to_json #Couldn't find all Tasks with 'id': (all, {:include=>{:people=>:name}})
end
我希望为开发人员,审阅者和其他对象提供嵌套json的Tasks json。 这个问题是对this。
的跟进答案 0 :(得分:0)
经过一番搜索后发现as_json(include: <association>)
所以这个工作
Task.includes(:developer,:reviewer).all.as_json(include: [:developer,:reviewer]).to_json
但还需要看到其他替代方案。