Question

我为纸牌游戏编写了以下代码。运行程序时我没有遇到任何错误。但是，有一件事我想改进。对于方法＆＃34; getSuit＆＃34;，我怎么能得到诉讼的全名，如俱乐部＆＃39;而不只是像＆＃39; c＆＃39;？

这样的简短名称

class Card: # One object of class Card represents a playing card
rank =['','Ace','Two','Three','Four','Five','Six','Seven','Eight','Nine','Ten','Jack','Queen','King']
suit = {'d':'Diamonds', 'c':'Clubs', 'h':'Hearts', 's':'Spades'}
def __init__(self, rank=2, suit=0): # Card constructor, executed every time a new Card object is created
    self.rank = rank
    self.suit = suit

def getRank(self): # Obtain the rank of the card
    return self.rank

def getSuit(self): # Obtain the suit of the card
    return self.suit

def bjValue(self): # Obtain the Blackjack value of a card
    Value = {'Ace':'1', 'Two':'2', 'Three':'3', 'Four':'4', 'Five':'5', 'Six':'6', 'Seven':'7', 'Eight':'8', 'Nine':'9', 'Ten':'10', 'Jack':'10', 'Queen':'10', 'King':'10'}
    return min(self.rank, 10)

def __str__(self): # Generate the name of a card in a string
    return "%s of %s" % (Card.rank[int(self.rank)], Card.suit[self.suit])


c1 = Card(1,'c')
print(c1)
print(c1.getRank())
print(c1.getSuit())
print(c1.bjValue())

# Output as below
>>> ================================ RESTART ================================
>>> 
Ace of Clubs
1
c
1
>>>

Answer 1

根据你所拥有的，最简单的方法可能是这样的：

def getSuit(self): # Obtain the suit of the card
    return Card.suit[self.suit]

但是，请记住，您正在混合实例变量和类变量。如果您不知道这意味着什么，请查看this stackoverflow thread。

如何在Python中以全名而不是短名称获得诉讼

1 个答案: