GetEnumerator在此上下文中不存在

时间:2015-02-06 16:08:04

标签: c# linked-list ienumerable ienumerator

我已经实现了自定义链接列表,但我在实现IEnumerator<>时遇到了问题。具体来说,编译器告诉我The name "GetEnumerator" does not exist in the current context。我觉得我实现它的方式正是我在众多stackoverflow帖子和教程中看到的,我缺少什么?

这是我的数据结构:

namespace TestReportCreator_v3
{
    public class FindingsTable : IEnumerable<string>
    {
        private Node head, mark;
        public class Node
        {
            public string description; //covers weakness, retinaDesc, nessusDesc
            public string riskLevel; //covers impactLevel, retinaRisk, nessusRisk
            public string boxName; //box name results apply to
            public string scanner; //wassp, secscn, retina, nessus
            public string controlNumber; //ia control number impacted, wassp and secscn only
            public string fixAction; //comments, retinaFix, nessusSolu
            public string auditID; //nessus plugin, retina AuditID, wassp/secscn test number
            public Node next;
            public Node(string auditID, string riskLevel, string boxName, string scanner, string controlNumber, string fixAction, string description, Node next)
            {
                this.description = description;
                this.riskLevel = riskLevel;
                this.boxName = boxName;
                this.scanner = scanner;
                this.controlNumber = controlNumber;
                this.fixAction = fixAction;
                this.auditID = auditID;
                this.next = next;
            }
        }

    ...insert, delete, update, save methods...

        public IEnumerator<string> IEnumerable<string>.GetEnumerator()
        {
            var node = mark;

            while (node != null)
            {
                yield return node.riskLevel;
                node = node.next;
            }
        }

        System.Collections.IEnumerator System.Collections.IEnumerable.GetEnumerator()
        {
            return GetEnumerator();
        }
    }
}

1 个答案:

答案 0 :(得分:6)

IEnumerable<string>.GetEnumerator()是一个显式接口实现,因此您需要在实例上调用它,作为接口访问。最简单的方法是投射this

return ((IEnumerable<string>)this).GetEnumerator();

有关替代方案,请参阅How to call explicit interface implementation methods internally without explicit casting?